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Mila [183]
3 years ago
9

Joseph gets married next month. One year ago from the date he will get married, Joseph was in the Hamptons for the 4th of July.

What month is it
Mathematics
2 answers:
Alik [6]3 years ago
7 0
The month would be June
melisa1 [442]3 years ago
5 0
It's June, because that's one month before July. 
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PLZ HURRY Thank you and have a nice day
irga5000 [103]

Answer:

multiply lol

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Whic
Nana76 [90]

Answer: 180 cm

Step-by-step explanation: 1 decimeter = 10 centimeter

18 dm = 10 * 18 cm

18 dm = 180 cm

Would appreciate brainly <3

3 0
3 years ago
A triangular pyramid with an equilateral base has a side length of 10 centimeters and a surface area of 214.5 square centimeters
Lady_Fox [76]
The answer is near 11.4
4 0
3 years ago
How do I make this bell curve
Zanzabum

The mean you found is correct, but the standard deviation is not. Recall that the standard deviation \sigma_s (s for sample) of n points is given by

\sigma_s=\sqrt{\dfrac1{n-1}\displaystyle\sum_{1\le i\le n}(x_i-\bar x)^2}

where n=10 is the sample size, \bar x=3740 is the sample mean, and x_i are the prices listed in the circled column. So

\sigma_s=\sqrt{\dfrac{(3640-3740)^2+(7595-3740)^2+\cdots+(3390-3740)^2}{10-1}}

\implies\sigma_s\approx1443.98\approx1444

I can't tell if you need to provide any more info beyond this, but given there's a plot of a generalized bell curve, I think you're also supposed to label the plot.

At the center of the bell-shaped/normal distribution is the mean. Notice there are three tick marks to either side of the mean - these are probably supposed to represent prices that fall exactly 1, 2, and 3 standard deviations from the mean. These are, from left to right,

\bar x-3\sigma_s\approx3740-3(1444)=-592

\bar x-2\sigma_s\approx3740-2(1444)=852

\bar x-\sigma_s\approx2296

\bar x+\sigma_s\approx5184

\bar x+2\sigma_s\approx6628

\bar x+3\sigma_s\approx8072

8 0
3 years ago
I WILL MARK YOU THE BRAINLIEST IF YOU ANSWER THIS CORRECTLY WITH WORK
saul85 [17]

Answer:

Students on Honor Roll had no advantage to get the Science class requested. It was a fair class assignment. In fact No Honor Roll students had advantage over honor Roll Students in obtaining Science Class as requested.  

Step-by-step explanation:

Here let us streamline the information we are given one by one

1.) Honor Roll

Get Requested Science Class                : 64

Did Not get  Requested Science Class : 80

Total                                                         : 144

Percentage of Honor Roll Students getting Science class as requested =

\frac{64}{144}

= 44.44%

2.) No Honor Roll

Get Requested Science Class               : 315

Did Not get Requested Science Class :  41

Total                                                         : 356

Percentage of Non Honor Roll Students getting Science class as requested = \frac{315}{356}

= 88.8%

By observing the above result , we can assume that Honor Roll students did not have any advantage over non Honor Roll students in getting Science Class as they requested.

3 0
4 years ago
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