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Mila [183]
3 years ago
9

Joseph gets married next month. One year ago from the date he will get married, Joseph was in the Hamptons for the 4th of July.

What month is it
Mathematics
2 answers:
Alik [6]3 years ago
7 0
The month would be June
melisa1 [442]3 years ago
5 0
It's June, because that's one month before July. 
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How to solve 1/2(1/3w+4)+6=10 and -5(h+4)=12
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\frac{1}{2}(\frac{1}{3}w+4)+6=10\\\\
\frac{1}{6}w+\frac{4}{2}+6=10\\\\
\frac{1}{6}w+2+6=10\\\\
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\frac{1}{6}w=2\ \ \ |Multiply\ by\ 6\\\\
\boxed{w=12}\\\\\\
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6 0
4 years ago
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What is the standard form of the equation of the circle in the graph
seraphim [82]
The standard form of the equation of a circle with center (h, k) and radius r is
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You have a circle centered at (-3, 1) with radius 1, so the standard form equation is
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5 0
3 years ago
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Solve x^2=2x+3 by factoring
solong [7]

The solution is x = 1 and x = -3

<em><u>Solution:</u></em>

Given that we have to solve the given equation by factoring

Given equation is:

x^2=2x + 3\\\\x^2 - 2x - 3 = 0

\text{Consider the form } x^2+bx+c

Find a pair of integers whose product is c and and whose sum is b

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Now find, a pair of integers whose sum is -2 and product is -3

The integers that satisfies this condition is -1 and 3

When we add - 1 and 3 we get 2

When multiply -1 and 3 we get -3

Thus the pair of integers are -1 and 3

Write the factored form using these integers.

(x-1)(x+3) = 0

The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0

Set the factors equal to 0

x - 1 = 0 \text{ and } x + 3 = 0

x = 1 and x = -3

Thus the solution is x = 1 and x = -3

4 0
3 years ago
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