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Whitepunk [10]
3 years ago
10

Find the value of x which ABCD must be a parallellogram? x =

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
3x-17=25-3x\\
6x=42\\
x=7
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What is the answer of 17 and 16 ​
Vera_Pavlovna [14]

Answer:

c)

Step-by-step explanation:

16) Cost price = Selling price  * 100 / (100- loss%)

= 800 * 100 / 80 = 10*100 = 1000

Loss = Cost Price - Selling price = 1000 -800 = 200

6 0
3 years ago
Are the functions linear or nonlinear?
inna [77]
Linear. They all follow the format y=mx+c wether or not they have been rearranged.
5 0
3 years ago
Read 2 more answers
A map has a scale of 2.5 inches=125 miles. If the actual distance is 300 miles what is the distance on the map
e-lub [12.9K]
Answer 5.5

Explanation 125 + 125= 250
250 + 50=300

Is 2 125s and 1 50

Each 125 is 2.5

But in this case there is 2 125s

2.5+2.5=5
plus the other half = 5.5

BRAINLIST?
4 0
3 years ago
A rectangular poster is to contain 722 square inches of print. the margins at the top and bottom of the poster are to be 2 inche
Delvig [45]
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need to minimize the area A=x*y

we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2

so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4

find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]

for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in

(y)=[722/(x-4)]+2

y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in

the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in

6 0
3 years ago
: A personal computer manufacturer buys 36% of its chips from Japan and the rest from the United St...
meriva

Answer: 0.9862

Step-by-step explanation:

Given : The probability that the chips belongs to Japan: P(J)= 0.36

The probability that the chips belongs to United States : P(U)= 1-0.36=0.64

The proportion of Japanese chips are defective : P(D|J)=0.017

The proportion of American chips are defective : P(D|U)=0.012

Using law of total probability , we have

P(D)=P(D|J)\times P(J)+P(D|U)\times P(U)\\\\\Rightarrow\ P(D)=0.017\times0.36+0.012\times0.64=0.0138

Thus , the probability that chip is defective = 0.0138

Then , the probability that a chip is defect-free=1-0.0138=0.9862

3 0
3 years ago
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