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Anna35 [415]
3 years ago
10

Four-fifths of the sum of k and 8 plus the product of 3 and n

Mathematics
1 answer:
deff fn [24]3 years ago
5 0

Answer:

(4/5)[K + 8] +3n

Step-by-step explanation:

(4/5) x [K + 8] + [ 3 x n]

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a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks​
Inessa [10]
<h3>The distance between two landmarks is 123 meters</h3>

<em><u>Solution:</u></em>

We have to find the distance between two landmarks

<em><u>Use the law of cosines</u></em>

The third side of a triangle can be found when we know two sides and the angle between them

c^2 = a^2 + b^2 - 2ab\ cos c

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123

Thus, the distance between two landmarks is 123 meters

8 0
4 years ago
Need help plzzzzz The first one and the second one plZ
solong [7]

From both sides of the equation, 4 should have been subtracted.

The solution should look like this:

X + 4  =  28

From each side, subtract  4 :

<em>X  =  24</em>

I'd like to demonstrate more steps, but the answer has already popped up, so there aren't any more steps.

4 0
4 years ago
How do I find the sides of a right triangle using sine, cos, or tan, with only the three angles and the hypotenuse
Yuki888 [10]

In this right triangle, you are given the measurements for the hypotenuse, c, and one leg, b. The hypotenuse is always opposite the right angle and it is always the longest side of the triangle. To find the length of leg a, substitute the known values into the Pythagorean Theorem. Solve for a2.

Hope this helps!

Please give brainliest!

4 0
3 years ago
The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R
Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2} $

P(0) = 300    P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$ \int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

        = 11,614

So the population becomes 11,614 after 8 days.

8 0
3 years ago
Using numbers 3, 6, and 8 to make 8.
Charra [1.4K]
I think it’s gonna be 3 and 5 to make 8
8 0
3 years ago
Read 2 more answers
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