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My name is Ann [436]
3 years ago
5

Need help plzzzzz The first one and the second one plZ

Mathematics
1 answer:
solong [7]3 years ago
4 0

From both sides of the equation, 4 should have been subtracted.

The solution should look like this:

X + 4  =  28

From each side, subtract  4 :

<em>X  =  24</em>

I'd like to demonstrate more steps, but the answer has already popped up, so there aren't any more steps.

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Help plz???? I need help with math
tekilochka [14]

Surface area is the area of the faces added together.

First lets find the area of one of the triangles.

Area of triangle is 1/2*base*hight

Area=1/2*2*3= 3

Area of ONE tringle is 3, and area of the FOUR tringles is 4*3 whihc is 12

Now lets find area of square

area of square is side*side

So, area is 2*2 which is 4

Now lets add area of triangles+area of square

12+4 which 16

Surface area is 16

6 0
2 years ago
On the graph, △DEF was transformed to create △DGH.
mafiozo [28]

Answer:

it's B

Step-by-step explanation:

by analyzing it I figured it was 100% B

8 0
2 years ago
Read 2 more answers
Nth term fo 3,11,25,45
alexandr1967 [171]
I think the answer may be 291
7 0
2 years ago
Read 2 more answers
what would you have to do the graph to find hoe many eggs needed if the recipe was larger and called for 16 tablespoon of water
AlexFokin [52]
I am sorry, that is not enough information. You have to show us the graph.
6 0
3 years ago
A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
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