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My name is Ann [436]
4 years ago
5

Need help plzzzzz The first one and the second one plZ

Mathematics
1 answer:
solong [7]4 years ago
4 0

From both sides of the equation, 4 should have been subtracted.

The solution should look like this:

X + 4  =  28

From each side, subtract  4 :

<em>X  =  24</em>

I'd like to demonstrate more steps, but the answer has already popped up, so there aren't any more steps.

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Identify vertex and y-intercept of graph of function y= -3(x+2)^2+5
Doss [256]
Hello,

Vertex=(-2,5)
x=0==>y=-3(0+2)²+5=-7

3 0
3 years ago
If there is 495,523 x 2-3x8 divided by 5 with ramanders
MrMuchimi

Answer:

991041.2

Step-by-step explanation:

You just have to use a calculator and the order of operations

5 0
3 years ago
WZ = 5.3 km, find the area of the shaded sectors to the nearest tenth. Please help
Jobisdone [24]

Answer: The area of the shaded sectors is 35.3 square kilometres

Step-by-step explanation: What we have here is a circle with center Z. Two sectors have been formed which are ZVW and ZYX. A careful observation reveals that both sectors are similar. If WY passes through the center Z then WY is a diameter. The same applies to VX, since it also passes through the center, therefore it is a diameter. Both lines intersect at the center, that makes both sectors to have the same radii which is  5.3 km and same applies to the angle subtended at the center of the sector, both angles are opposite angles formed by intersecting lines (opposite angles formed by intersecting lines are equal). On a straight line WY, the sum of angles ∠WZX and ∠YZX equals 180 degrees (Sum of angles on a straight line equals 180). Therefore;

WZX + YZX = 180

108 + YZX = 180

Subtract 180 from both sides of the equation

YZX = 72°

Therefore the area of shaded sector YZX is given as;

Area of a sector = (∅/360) x πr²

Where ∅ is 72, and r is 5.3

Area of sector = (72/360) x 3.14 x 5.3²

Area of sector = 0.2 x 3.14 x 28.09

Area of sector = 17.64

Having in mind that both sectors are similar (the same radii and the same central angle), the area of the shaded sectors shall be equal to 17.64 times 2 and that equals 35.28. (That is approximately 35.3 to the nearest tenth)

The area of the shaded sectors therefore is 35.3 square kilometres (35.3 km²)

3 0
4 years ago
Read 2 more answers
The middle note C has a frequency of 262 hertz and can be modeled using a sine function with an amplitude of 1.5, where x is tim
MrRissso [65]

Answer:  f(x) = 1.5*sin(x*2*pi/0.0038s)

Step-by-step explanation:

A sine function is:

f(x) = A*sin(c*x + f)

Where A is the amplitude, we know that it is 1.5

c is a constant that depends on the frequency.

f is a phase.

As there is no mention of a phase, we can assume f = 0.

Then our function is:

f(x) = 1.5*sin(c*x)

now let's find the value of c.

We know that the frequency is 262hz.

Then the period can be calculated with the equation:

T = 1/f.

T = 1/262 Hz = 0.0038 seconds.

Now, the period of a sin function is 2*pi.

whit pi = 3.14159265358979.....

Then we have that:

sin(0) = sin(c*0.0038s)

sin(0) = sin(2*pi)

then:

c*0.0038s = 2*pi

c = 2*pi/0.0038s

Then the function is:

f(x) = 1.5*sin(x* 2*pi/0.0038s)

3 0
3 years ago
Read 2 more answers
Determine the most precise name for the quadrilateral with vertices at A(–7, –2), B(0, 2), C(4, –5), and D(–3, –9).
Ghella [55]

All angles are 90 degrees, which cancels out a kite and a rhombus, leaving you with two options (rectangle or square). Using Pythagoras' theorem, you can work out that all sides are also of equal length, which means this shape is a square :)

3 0
4 years ago
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