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slava [35]
3 years ago
5

Will give brainliest

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer:

x^2 + 4x + 4

Step-by-step explanation:

Elina [12.6K]3 years ago
4 0

Answer:

quadratic: y = x^2 + 4x + 4

Step-by-step explanation:

Notice that each y value is the square of an integer.

4 = 2^2

9 = 3^2

16 = 4^2

etc.

This is a quadratic equation.

The first ordered pair is (0, 4). 4 is 2^2, so add 2 to x and rthen square the quantity. (0 + 2)^2 = 2^2 = 4. This also works for the other values of x.

The equation is

y = (x + 2)^2

y = x^2 + 4x + 4

Answer: quadratic: y = x^2 + 4x + 4

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Shawn says that 3.22 is a rational number. Leah says 3.22 is a repeating decimal. Who is correct and why?
MAVERICK [17]

Answer:

Hi, There! Leah Is Correct

Step-by-step explanation:

A fraction is a repeating decimal if the prime factors of the denominator of the fraction in its lowest form do not only contain 2s and/or 5s or do not have any prime factors at all.

____________________________________________________________

-Darkspirit-

3 0
2 years ago
Read 2 more answers
WHICH ANSWER IS CORRECT?!?!?
Anna007 [38]
The answer is d because a horizontal line has a slope of zero.
6 0
2 years ago
The first 5 terms of a sequence are shown below:
nirvana33 [79]

Step-by-step explanation:

To find the formula for the nth term ,

First , find the common difference or common ratio.

Common difference =

T_2-T_1 \\  - 2 - 3 \\  =  - 5

Common ratio =

T_2/T_1 \\  \frac{ - 2}{3}

The common difference applies to the other given numbers for example :

T_3- T_2  =  - 7 - ( - 2) \\  =  - 7 + 2 =  - 5

this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is

T_n =a(n-1)d

Where n = no of terms

a= first term

d= common difference

6 0
3 years ago
A sample of tritium-3 decayed to 94.5% of its original amount after a year.
Zolol [24]
(a) If y(t) is the mass after t days and y(0) = A then y(t) = Ae^{kt}.

y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945

\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\  ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}

(b)
Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}
3 0
3 years ago
Solve this answer<br> 5/3 + 2/5
salantis [7]
5/3+2/5=25/15+6/15=31/15=2 1/15

2 1/15 or 31/15

5 0
3 years ago
Read 2 more answers
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