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4 years ago

Will give brainliest

Mathematics

2 answers:

Evgen [1.6K]4 years ago

7 0

Answer:

x^2 + 4x + 4

Step-by-step explanation:

Elina [12.6K]4 years ago

4 0

Answer:

quadratic: y = x^2 + 4x + 4

Step-by-step explanation:

Notice that each y value is the square of an integer.

4 = 2^2

9 = 3^2

16 = 4^2

etc.

This is a quadratic equation.

The first ordered pair is (0, 4). 4 is 2^2, so add 2 to x and rthen square the quantity. (0 + 2)^2 = 2^2 = 4. This also works for the other values of x.

The equation is

y = (x + 2)^2

y = x^2 + 4x + 4

Answer: quadratic: y = x^2 + 4x + 4

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3 years ago

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3 years ago

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3 years ago

Determine the equations of the vertical and horizontal asymptotes if any for h(x)=(x+1)^2/x^2-1

shepuryov [24]

ANSWER

Vertical asymptote:

x=1

Horizontal asymptote:

y=1

EXPLANATION

The given rational function is

$h(x) = \frac{ {(x + 1)}^{2} }{ {x}^{2} - 1 }$

$h(x) = \frac{ {(x + 1)}^{2} }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ (x + 1)(x + 1) }{ ({x} - 1)(x + 1)}$

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The vertical asymptote occurs at

${x} - 1 = 0$

$x = 1$

The vertical asymptotes is x=1

The degree of the numerator is the same as the degree of the denominator.

The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.

$y = \frac{1}{1}$

y=1

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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