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2 years ago

L.C.M 5= 12= explain??

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

7 0

60 because 5 x 12 = 60 and 12 x 5 = 60 are the smallest corresponding umbers.

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Find the angle 0 between the vectors. u=(1, 1, 1, 0), v = (4, 4, 4, 4).

Naya [18.7K]

Answer:

30 degrees

Step-by-step explanation:

u dot v=1*4+1*4+1*4+0*4=4+4+4+0=12

|u|=sqrt(1^2+1^2+1^2+0^2)=sqrt(3)

|v|=sqrt(4^2+4^2+4^2+4^2)=sqrt(4*4^2)=2*4=8

cos(theta)=u dot v/(|u||v|)

cos(theta)=12/(sqrt(3)*8)

cos(theta)=3/(sqrt(3)*2)

cos(theta)=sqrt(3)/2

theta=30 degrees

6 0

2 years ago

Plz answer my question

Drupady [299]

Answer:

2a^4 / b^5

Step-by-step explanation:

(2a^2 / b) x ( a / b^2) ^2

= (2a^2 / b) x (a^2 / b^4)

= 2a^4 / b^5

(p.s if you are not gonna do it don't say "no thanks" and leech off this poor man's points)

3 0

2 years ago

List x1, x2, x3, x4 where xi is the left endpoint of the four equal intervals used to estimate the area under the curve of f(x)

n200080 [17]

Answer:

Option A. 4, 4.5, 5, 5.5

Step-by-step explanation:

Left point: a=x=4

Right point: b=x=6

Range: r=b-a→r=6-4→r=2

Width of each of the four equal intervals: w=2/4→w=0.5

The first left endpoint is x1=a→x1=4

The second left endpoint is x2=x1+w→x2=4+0.5→x2=4.5

The third left endpoint is x3=x2+w→x3=4.5+0.5→x3=5

The fourth left endpoint is x4=x3+w→x4=5+0.5→x4=5.5

Then, the list is: x1, x2, x3, x4 = 4, 4.5, 5, 5.5

4 0

2 years ago

You supervise the feeding of dogs at a kennel you use an average of 10 1/2 pounds of dog food each day.at the rate how many poun

liq [111]

Answer:

73.5 pounds of dog food in 7 days

Step-by-step explanation:

10 1/2 x 7

10x 7 =70

1/2 x 7 = 3.5

70 + 3.5 =73.5 pounds of dog food in 7 days

6 0

1 year ago

The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t

astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)= $\frac{ME*\sqrt{N}}{s }$ where

Me is the margin of error from the mean

s is the standard deviation of the population

N is the sample size

z(p)= $\frac{8*\sqrt{30}}{50 }$ ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

z(p)= $\frac{8*\sqrt{50}}{50 }$ ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

z(p)= $\frac{8*\sqrt{100}}{50 }$ ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

Minimum required sample size for 0.95 probability is

N≥ $(\frac{z*s}{ME} )^2$ where

N is the sample size

z is the corresponding z-score in 95% probability (1.96)

s is the standard deviation (50)

ME is the margin of error (8)

then N≥ $(\frac{1.96*50}{8} )^2$ ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0

2 years ago

L.C.M 5= 12= explain??​

L.C.M 5= 12= explain??