Question

Write in slope-intercept form an equation of a line that passes through the given points. (1,6) and (3,2)

Answer 1

Answer: y = -2x + 8

Step-by-step explanation:

To find the equation of the line , we will use the formula:

$\frac{y_{2}- y_{1}}{x_{2}- x_{1}}$ = $\frac{y-y_{1}}{x - x_{1}}$

From the question

$x_{1}$ = 1

$x_{2}$ = 3

$y_{1}$ = 6

$y_{2}$ = 2

substituting into the formula , we have

$\frac{2 - 6}{3 - 1}$ = $\frac{y - 6}{x - 1}$

$\frac{-4}{2}$ = $\frac{y - 6}{x - 1}$

cross multiplying , we have

2(y-6) = -4(x-1)

Expanding , we have

2y - 12 = -4x + 4

Adding 12 to both sides , we have

2y = -4x + 16

dividing through by 2 , we have

y = -2x + 8

Therefore , the equation of the line is given as

y = -2x + 8