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patriot [66]
3 years ago
14

Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20, 0).

Mathematics
2 answers:
Debora [2.8K]3 years ago
7 0

Answer:

Option C). (10, 7.5)

Step-by-step explanation:

We have to find the coordinates of point M that divides the segment AB into a ratio of 5:5.

Vertices A and B are (0, 15) and (20, 0)

Ratio 5:5 is simply the ratio 1:1 means point M is the midpoint of segment AB.

So x-coordinate of M will be \frac{(20+0)}{2}=10

and y - coordinate will be = \frac{(15+0)}{2}=7.5

Therefore Option C. (10, 7.5) are the coordinates of point M.

Airida [17]3 years ago
5 0

C

a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment

using the midpoint formula

M = [\frac{1}{2} (0 + 20 ), \frac{1}{2} (15 + 0)] = (10, 7.5 )


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1

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1

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2

+

R

3

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3

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⎥

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⎡

⎢

⎣

1

−

1

1

2

3

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3

−

2

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9

|

8

−

2

9

⎤

⎥

⎦

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2

R

1

+

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2

=

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→

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⎣

1

−

1

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0

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−

3

3

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2

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9

|

8

−

18

9

⎤

⎥

⎦

−

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R

1

+

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3

=

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⎣

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−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

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​2

​​  and \displaystyle {R}_{3}R

​3

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Interchange

R

2

and

R

3

→

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⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

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2

+

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3

=

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3

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⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

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57

⎤

⎥

⎦

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⎣

1

−

1

1

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1

−

12

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0

1

|

8

−

15

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⎥

⎦

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−

y

+

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