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patriot [66]
3 years ago
14

Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20, 0).

Mathematics
2 answers:
Debora [2.8K]3 years ago
7 0

Answer:

Option C). (10, 7.5)

Step-by-step explanation:

We have to find the coordinates of point M that divides the segment AB into a ratio of 5:5.

Vertices A and B are (0, 15) and (20, 0)

Ratio 5:5 is simply the ratio 1:1 means point M is the midpoint of segment AB.

So x-coordinate of M will be \frac{(20+0)}{2}=10

and y - coordinate will be = \frac{(15+0)}{2}=7.5

Therefore Option C. (10, 7.5) are the coordinates of point M.

Airida [17]3 years ago
5 0

C

a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment

using the midpoint formula

M = [\frac{1}{2} (0 + 20 ), \frac{1}{2} (15 + 0)] = (10, 7.5 )


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A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9
geniusboy [140]

Answer:

7.7 km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 6.6 km and 3.9 km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, a^{2}+b^{2} =c^{2}, where a and b are the lengths of the triangle's legs and c is the length of the triangle's hypotenuse. In this case, we know what a and b are, and we need to solve for c, so after substituting the given values of a and b into a^{2}+b^{2} =c^{2} to solve for c, we get:

a^{2}+b^{2} =c^{2}

6.6^{2} +3.9^{2} =c^{2} (Substitute a=6.6 and b=3.9 into the equation)

43.56+15.21=c^{2} (Evaluate the squares on the LHS)

58.77=c^{2} (Simplify the LHS)

c^{2}=58.77 (Symmetric Property of Equality)

\sqrt{c^{2} } =\sqrt{58.77} (Take the square root of both sides of the equation)

c=7.7,c=-7.7 (Simplify)

c=-7.7 is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately 7.7 km away from its base. Hope this helps!

7 0
3 years ago
Help picture attached
Vilka [71]
I would say c or d. but since its multiple choice, its ok to guess sometimes.
6 0
3 years ago
Find the quotient of and express it in the simplest form
nirvana33 [79]

Answer:

No answer can be found

Step-by-step explanation:

There isn't any value to find and express in simplest form lol.

5 0
3 years ago
4 + 2x2(3x-5)<br> number of terms
igor_vitrenko [27]
3, assuming 2x2 is 2x squared, u will get
4 + 6x3 - 10x2

So 3 terms
7 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
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