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2 years ago

Let f ( ) sin(arctan ) x x = . What is the range of f ?

1 answer:

5 0

So you have composed two functions,
h(x)=sin(x) and g(x)=arctan(x)
→f=h∘g
meaning
f(x)=h(g(x))
g:R→[−1;1]
h:R→[−π2;π2]
And since
[−1;1]∈R→f is defined ∀x∈R

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]
Meaning
f:R→[arctan(−1);arctan(1)]=[−π4;π4]
so there's your domain

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Y-1=0 is what form: Standard Point-Slope Form Brainliest for first Answer

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2 years ago

HURRY PLEASE When 5 and 6 are multiplied by the same factor, how do the ratios compare to the ratio 5:6? The ratios are equivale

erma4kov [3.2K]

Answer:

The ratios are equivalent.

Step-by-step explanation:

If you multiply both 5 and 6, the ratio stays the same.

5:6 = 10:12 = 15:18 = 20:24 etc.

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2 years ago

Clara has a package of six cookies she wants to share equally among her friends if Claire make sure that each piece of cookie wi

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Answer:

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2 years ago

1) Suppose you put money into two different bank accounts. In account #1 you deposit $500 and you will be earning 6% interest co

Elis [28]

The answer for number 1 is D they will have the same amount of money.

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3 years ago

Read 2 more answers

I NEED HELP !!! 30 points!!!! and brainliest :) please give sensible answer :(

Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> $\frac{180-x}{2}+45=115 \\$

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS is an isosceles triangle => ∠TQS = 180 -2x

QRS is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => $\left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.$

=> x + y = 80

12) EFJ Is an equilateral triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0

2 years ago