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2 years ago

What is the Translation Postulate?

Mathematics

1 answer:

natali 33 [55]2 years ago

5 0

Answer: to suggest or accept that a theory or idea is true as a starting point for reasoning or discussion.

Step-by-step explanation:

Here's an example: Astronomers postulate that the comet will reappear in 4000 years.

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Convert the point-slope form to slope-intercept form y– 4 = -3(x + 2)

artcher [175]

Answer:

y = -3x - 2.

Step-by-step explanation:

y - 4 = -3(x + 2)

y - 4 = -3x - 6

y = -3x - 6 + 4

y = -3x - 2.

4 0

3 years ago

Phil's average is 0.250. This is about 5/6 as much as Joe's average. What is Joe's average? (Write answer is decimal form - do n

LenaWriter [7]

Let Joes average = x

Phil’s average is 0.250 and is 5/6X ( 5/6 of Joe’s)

5/6x = 0.250

Solve for x by dividing both sides by 5/6. When dividing by a fraction, flip the fraction over and multiply;

X = 0.250 x 6/5 = (0.250 x 6)/5 = 1.5/5 = 0.30

Joes average is 0.3

5 0

2 years ago

Write and solve an equation for the word problem. Reagan drove

telo118 [61]

If you divide 287 by 77, it should take about 3 hours (rounded)

6 0

2 years ago

Isabella is calculating the interest earned on a deposit of $3000 in an account that earns 4% simple interest after 6 years I=pr

Delvig [45]

Answer:

Interest = $ 720

Step-by-step explanation:

p = $ 3000

r = 4%

t = 6

I = $3000*\frac{4}{100}*6\\$

= 30 *4 * 6

= 720

Amount = p + I

= 3000 + 720

= $ 3720

7 0

2 years ago

Trigonometric question, 30 points, will give brainliest.

Elis [28]

$\bf \textit{ roots of complex numbers, DeMoivre's theorem} \\\\ \sqrt[n]{z}=\sqrt[n]{r}\left[ cos\left( \cfrac{\theta+2\pi k}{n} \right) +i\ sin\left( \cfrac{\theta+2\pi k}{n} \right)\right]\quad \begin{array}{llll} k\ roots\\ 0,1,2,3,... \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left[ 32\left[ cos\left( \frac{\pi }{3} \right) +i~sin\left( \frac{\pi }{3} \right) \right] \right]^{\frac{1}{5}}$

$\bf 32^{\frac{1}{5}}\left[ cos\left( \frac{\pi +2\pi (0)}{15} \right)+i~sin\left( \frac{\pi +2\pi (0)}{15} \right) \right]\implies \stackrel{\textit{first root, k = 0}}{2\left[ cos\left( \frac{\pi }{15} \right)+isin\left( \frac{\pi }{15} \right) \right]}$

$\bf 32^{\frac{1}{5}}\left[ cos\left( \frac{\pi +2\pi (1)}{15} \right)+i~sin\left( \frac{\pi +2\pi (1)}{15} \right) \right]\implies \stackrel{\textit{second root, k = 1}}{2\left[ cos\left( \frac{7\pi }{15} \right)+isin\left( \frac{7\pi }{15} \right) \right]} \\\\\\ \stackrel{\textit{third root, k = 2}}{2\left[ cos\left( \frac{13\pi }{15} \right)+isin\left( \frac{13\pi }{15} \right) \right]}\qquad \bigotimes$

$\bf \stackrel{\textit{fourth root, k = 3}}{2\left[ cos\left( \frac{19\pi }{15} \right)+isin\left( \frac{19\pi }{15} \right) \right]}\qquad \bigotimes \\\\\\ \stackrel{\textit{fifth root, k =4}}{2\left[ cos\left( \frac{5\pi }{3} \right)+isin\left( \frac{5\pi }{3} \right) \right]}\qquad \bigotimes$

6 0

2 years ago