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horsena [70]
3 years ago
13

Please help and show ur work:)

Mathematics
1 answer:
Sidana [21]3 years ago
6 0
3/4...there’s no work to show
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Answer choices:<br><br> X=23<br><br> X=63<br><br> X=90
Law Incorporation [45]

Answer:

x = 63

Step-by-step explanation:

x + 2 + 25 = 90

x + 27 = 90

x = 63

I hope that helps.

3 0
3 years ago
Read 2 more answers
Can someone help me with my delta math assignments i'll give you brainiest and 80 points or more
Anettt [7]

sure what is it about maybe I can help you if it's possible

3 0
2 years ago
5<br> The slope of EF is<br> Which segments are perpendicular to EF?<br> Select each correct answer.
Anvisha [2.4K]

Answer:

the first two answers are perpendicular

8 0
2 years ago
How do I do this question folks?
horsena [70]

Answer:

Correct answer: B

Step-by-step explanation:

Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.

In the graph, you can see that the graph is defined for -3\leq x < 1 (not-including 1 because there is an open hole there, indicating it is not part of the domain), and 2\leq x\leq 4.

Now that we know the domain, we can attach it to the graphs that lie on those domains.

We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.

At this point, you can just start crossing off answers that don't meet this criteria.

Cheers!!

7 0
3 years ago
Pada hari kantin sebanyak 800 naskah kupon telah dijual,harga senaskah kupon masing masing rm 30 dan rm 50 .jumlah wang diperole
solniwko [45]

Answer:

Step-by-step explanation:

On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?

Let:

RM 30 = x

RM 50 = y

x + y = 800 - - - (1)

30x + 50y = 30000 - - - (2)

From (1)

x = 800 - y

Put x = 800 - y in (2)

30(800 - y) + 50y = 30000

24000 - 30y + 50y = 30000

24000 + 20y = 30000

20y = 30000 - 24000

20y = 6000

y =

4 0
3 years ago
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