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3 years ago

PLZ help Asap!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

maria [59]3 years ago

3 0

I'm may not be that good at math, but I'm going to try my best to help you, because I know how it feels to be in this situation!

The first one :
You might be right on D. But I'm thinking B also. The question asks "Which could be a cross section of a rectangular pyramid that has been intersected by a plane perpendicular". But a triangle is basically a flat pyramid.

(I'm typing really fast to help!!!!)

Second one: Its B!! Look at it really closely! You'll get it!!!

(Going really fast now!!!!)

Third one: Between B or D!!! But I think you're right on your choice!!!!

(FASTER FASTER!!!)

FINALLY: Copy and paste your answers into google. People have asked the same question!

I hope I helped. I don't want to make you fail, as I am in the SAME similar situation as you! I really REALLY REALLY HOPE YOU PASS!!!

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2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode

marusya05 [52]

$\text {Hi! Let's Solve this Problem!}$

$\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}$

$\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}$

$\underline {\text {Mean}}$

$\text {To Find the Mean you must Add all the Numbers then Divide.}$

$\text {Add:}$ $\text 80+80+83+84+85+87+91+96+97=\fbox {783}}$

$\text {Divide:}$ $\text {783/9=}$

$\text {The Mean Is:}$

$\fbox {87}$

$\underline {\text Median}}$

$\text {To find the Median you find the number that's in the middle of the set.}$

$\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}$

$\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}$

$\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87}$ $\text {it shows that 85 is left in the middle.}$

$\text {The Median Is:}$

$\fbox {85}$

$\underline {\text {Mode}}$

$\text {Finding the Mode means finding the number}$ $\text { that shows the most in the number set given.}$

$\text {Since 80 is the number that is showing more than any other number}$ $\text {this tells us that 80 is our Mode.}$

$\text {The Mode Is:}$

$\fbox {80}$

$\text {Best of Luck!}$

4 0

3 years ago

Prove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle, the sum of the s

aivan3 [116]

For the answer to the question above asking to p<span>rove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle,
</span>A right triangle consists of two sides called the legs and one side called the hypotenuse (c²) . The hypotenuse (c²)<span> is the longest side and is opposite the right angle.

</span>⇒ α² + β² = c²
<span>
"</span>In any right triangle ( 90° angle) <span>, the sum of the squared lengths of the two legs is equal to the squared length of the hypotenuse."
</span>
For example: Find the length of the hypotenuse of a right triangle if the lengths of the other two sides are 3 inches and 4 inches.
c2 = a2+ b2
c2 = 32+ 42
c2 = 9+16
c2 = 15
c = sqrt25
c=5

8 0

3 years ago

What is a reasonable estimate for the volume of a number cube:<br> 8 cm3, 27 in?, or 1 ft??

LuckyWell [14K]

Answer:

just beweve

Step-by-step explanation:

3 0

3 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

7 0

2 years ago

Suppose a scientist has 13 liters of acid and she needs 16 liters for an experiment.

vekshin1

B cause 13 plus x is equal to the 16 liters that u need and u already have 13 liters

3 0

3 years ago