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3 years ago

10

PLZ help Asap!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

maria [59]3 years ago

3 0

I'm may not be that good at math, but I'm going to try my best to help you, because I know how it feels to be in this situation!

The first one :
You might be right on D. But I'm thinking B also. The question asks "Which could be a cross section of a rectangular pyramid that has been intersected by a plane perpendicular". But a triangle is basically a flat pyramid.

(I'm typing really fast to help!!!!)

Second one: Its B!! Look at it really closely! You'll get it!!!

(Going really fast now!!!!)

Third one: Between B or D!!! But I think you're right on your choice!!!!

(FASTER FASTER!!!)

FINALLY: Copy and paste your answers into google. People have asked the same question!

I hope I helped. I don't want to make you fail, as I am in the SAME similar situation as you! I really REALLY REALLY HOPE YOU PASS!!!

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The measure of arc BCD is

makkiz [27]

Answer:

m∠BCD = 140°

Step-by-step explanation:

ABCD is cyclic quadrilateral. A property of cyclic quadrilateral states that the opposite angles of it sum up to 180°. Here:

m∠A + m∠C =180° and m∠B + m∠D = 180°

So, m∠A + m∠C =180°

m∠A = 40° (given in the question)

40° + m∠C = 180°

m∠C = 180° - 40° = 140°

∴m∠C = m∠BCD = 140°

6 0

3 years ago

Write three million five hundred twenty six thousand two hundred forty five in standard form

Temka [501]

3,526,245 is the answer.

3 0

3 years ago

Read 2 more answers

I can find the perimeter and area of the rectangle

Svetllana [295]

Answer:

A = 72, P = 38

Step-by-step explanation:

Area can be found by getting the area of the overall figure, and then subtracting the blank space in the corner

12 * 7 = 84

3 * 4 = 12(invisible rectangle in top right)

84 - 12 = 72

Perimeter can be found by adding all of the sides

12 + 7 + (12-4) + 3 + 4 + (7-4)

The numbers in brackets are the unlabeled sides on the top and left.

4 0

2 years ago

Read 2 more answers

Please help will mark brainliest

TEA [102]

we know that

total of sum of arc is 360

so, sum of both arc must be 360

so, we get

$90+x=360$

now, we can solve for x

$90+x-90=360-90$

$x=270$ ............Answer

6 0

3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago