Can you help me find the absolute min and max? <br> y=-2x² + 12x

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

Will give brainliest to correct answer.

ryzh [129]

We can solve this problem by seeing at which part both of the parts of the graphs of the function are discontinued. Both of the parts of the graph of the function are discontinued at -2, so we will have to find a function that has a value that is undefined for x = -2. We can do this using the denominator of the fraction that's in each of the functions. The function where x = -2 will cause it to be undefined is the third one, so the answer to this question is C., f (x) = $\frac{1}{x+2}$ +5.

4 0

4 years ago

Can someone please help me with this I will also give brainliest.

Sindrei [870]

Answer:

C) 3*10^6

Step-by-step explanation:

Divide the two numbers:

(6*10^-2)/(2*10^-8)=6/2*(10^-2/10^-8)=3*10^(-2-(-8))=3*10^(-2+8)=3*10^6

So C is correct

8 0

3 years ago

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A student was given two data sets, Set A and Set B. Which of the following statements is true?

guajiro [1.7K]

D

Step-by-step explanation:

3 0

3 years ago

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234/8 as a mixed number

uysha [10]

Calculate out how many times the denominator goes into the numerator. To do that, divide 234 by 8 and keep only what is to the left of the decimal point:

8 0

3 years ago

Can you help me find the absolute min and max? y=-2x² + 12x – 20; [2, 4]