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Deffense [45]
3 years ago
6

How to find the perimeter of a triangle

Mathematics
2 answers:
Mariulka [41]3 years ago
8 0

Answer:

s+s+s=p

Step-by-step explanation:

Just add the three side measurements. Answer will contain a unit most of the time. Remember to convert units if its asking for different units.

Alecsey [184]3 years ago
4 0

Answer:

Analyze then add

Step-by-step explanation:

Basically, just analyze the lengths of the sides, and then add them together for the perimeter

Thank me later :)

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The range of a data set is 18. if the smallest number in the set is 9, What is the largest number?
tankabanditka [31]
Range is the difference between the largest and the smallest variable. If the range is 18 and the smallest number is 9. Add 9 to 18.
9+18= 27. 27 is the largest number.
7 0
3 years ago
Can you help me please?
wel
The correct answer is true because the number do not repeat
3 0
3 years ago
Y''+y'+y=0, y(0)=1, y'(0)=0
mars1129 [50]

Answer:

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form ay''+by'+cy=0.

Given: y''+y'+y=0

Let y=e^{rt} be it's solution.

We get,

\left ( r^2+r+1 \right )e^{rt}=0

Since e^{rt}\neq 0, r^2+r+1=0

{ we know that for equation ax^2+bx+c=0, roots are of form x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} }

We get,

y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}

For two complex roots r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta, the general solution is of form y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )

i.e y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Applying conditions y(0)=1 on e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right ), c_1=1

So, equation becomes y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

On differentiating with respect to t, we get

y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )

Applying condition: y'(0)=0, we get 0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}

Therefore,

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

3 0
3 years ago
I believe the answer is C. however, I'm not 100% sure.
Brut [27]

The answer would be C. You’re correct! Because there are 3 blue marbles @ $1 each that amounts to a possible $3 gain for Mark. Evan has the chance to get $4. Cayla also can make $3 like Mark.

7 0
3 years ago
Sarah bought 3 pounds of apples for $6 . How much did each pound of apples cost ?
viva [34]

Answer:

A

Step-by-step explanation:

6/3 = 2

6 0
3 years ago
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