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Pie
4 years ago
7

Evaluating algebraic expressions 8(x+2)when x =6

Computers and Technology
1 answer:
Helen [10]4 years ago
6 0

Answer:

64

Explanation:

we know x equals 6 so the equation becomes 8(6+2). multiply 6 * 8 and 8 * 2 then add the result of 8 * 2 + 6 * 8 together.

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The function in Python is as follows:

import math

import numpy as np    

def exp(x):

   mylist = []

   for n in range(10):

       num = (x**n)/(math.factorial(n))

       mylist.append([num])

   exp_approx = np.asarray(mylist)

   sum = 0

   for num in exp_approx:

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   return sum

Explanation:

The imports the python math module

import math

The imports the python numpy module

import numpy as np    

The function begins here

def exp(x):

This creates an empty list

   mylist = []

This iterates from 0 to 9

   for n in range(10):

This calculates each term of the series

       num = (x**n)/(math.factorial(n))

This appends the term to list, mylist

       mylist.append([num])

This appends all elements of mylist to numpy array, exp_approx

   exp_approx = np.asarray(mylist)

This initializes the sum of the series to 0

   sum = 0

This iterates through exp_approx

   for num in exp_approx:

This adds all terms of the series

       sum+=num

This returns the calculated sum

   return sum

3 0
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