What is the last step in planning your budget

In the following cell, we've loaded the text of Pride and Prejudice by Jane Austen, split it into individual words, and stored t

Sever21 [200]

Answer:

Explanation:

Since the array is not provided, I created a Python function that takes in the array and loops through it counting all of the words that are longer than 5. Then it returns the variable longer_than_five. To test this function I created an array of words based on the synapse of Pride and Prejudice. The output can be seen in the attached picture below.

def countWords(p_and_p_words):

longer_than_five = 0

for word in p_and_p_words:

if len(word) > 5:

longer_than_five += 1

return longer_than_five

7 0

3 years ago

What does start immediately after the work is created and fixed into physical or digital form?

Tatiana [17]

its on google , just google it :)

3 0

3 years ago

Read 2 more answers

According to the text, the judicious use of elements such as bullets, numbers, boldface, italics, and capitalization in document

kaheart [24]

Answer:

Facilitating interactivity.

Providing visual variety.

Emphasizing key information.

Explanation:

The judicious use of these elements helps the author in various different ways. These characters facilitate the interaction of the reader with the text by making it easier for him to understand the best way to proceed with the reading. Moreover, they provide visual variety, which makes information easier to process for the reader. Finally, these characters also emphasize key information, helping with reading comprehension.

6 0

3 years ago

True or false?

sashaice [31]

True cars are fast and go fast

6 0

3 years ago

Read 2 more answers

You are working for the census bureau and you need to write a program in C to do the following: a) count the number of people in

valina [46]

Answer:

See explaination

Explanation:

#include<iostream>

#include<stdio.h>

#include<conio.h>

#include<math.h>

using namespace std;

void main()

{

int RandomData[]={10,5,20,45,20,66,25,31,20,70}; //Random Data

int infant=0,young=0,middle=0,old=0,older=0; //To store count

int n,freq,count=0,high=0; //to store mode and other

double stdDev,mean,sum=0; //to store stdDev mean and sum

for(int i=0;i<(sizeof(RandomData)/sizeof(RandomData[0]));i++) //loop to count

{

if(RandomData[i]>0&&RandomData[i]<=18)

infant++;

else if(RandomData[i]>18&&RandomData[i]<=29)

young++;

else if(RandomData[i]>29&&RandomData[i]<=50)

middle++;

else if(RandomData[i]>50&&RandomData[i]<=69)

old++;

else if(RandomData[i]>69)

older++;

}

double first=0,sec=0; //to store result of stdDev formula first and second part

for(int i=0;i<(sizeof(RandomData)/sizeof(RandomData[0]));i++) //loop to calculate mean mode and stdDev

{

n=RandomData[i];

count=0;

for(int j=0;j<(sizeof(RandomData)/sizeof(RandomData[0]));j++)

{

if(n==RandomData[j])

count++;

}

if(high<count)

{

freq=RandomData[i];

high=count;

}

first+=(pow((RandomData[i]),2)/(sizeof(RandomData)/sizeof(RandomData[0])));

sec+=RandomData[i]/(sizeof(RandomData)/sizeof(RandomData[0]));

sum+=RandomData[i];

}

mean=sum/(sizeof(RandomData)/sizeof(RandomData[0]));

stdDev=sqrt(first-pow((sec),2));

/*------Printing Result-----*/

cout<<"\nCount:\nInfant: "<<infant<<"\nYoung: "<<young<<"\nMiddle: "<<middle;

cout<<"\nOld: "<<old<<"\nOlder: "<<older;

cout<<"\n\nMean: "<<mean<<"\nMode: "<<freq<<"\nStandard Deviation: "<<stdDev;

/*-----------XXXX-------------*/

getch();

}

8 0

3 years ago