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4 years ago

Item 7

1 answer:

4 0

For this item, all we have to identify is the area of the hanging light cover. Because it is said that it does not have a cover, we are only concerned about the lateral area which is equal to
Lateral area = 4(x)(l)/2 = 2xl
where x is the measure of the side of the square base and l is the length of the slant height.
After calculating the area in square foot, we multiply this to 2.45 pounds/ft², if the obtained value is ≤ 35 then, the chain can support the light cover.

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Can someone help please and thank you!

kondor19780726 [428]

Answer:

10 and 40 I think maybe?

Step-by-step explanation:

I hope this is correct if not I am so so so so so so sorry

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3 years ago

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The video streaming service that you want to use is represented with the equation below, where y represents the the total monthl

Dominik [7]

Answer:

It’s 11.25

Step-by-step explanation:

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3 years ago

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Semenov [28]

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4 years ago

A survey found that women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also

Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that women's heights are normally distributed.

Population mean : $\mu =63.2 \text{ inches}$

Standard deviation: $\sigma= 2.4\text{ inches}$

Minimum height = 4ft. 9 in.= $4\times12+9\text{ in.}=57\text{ in.}$

Maximum height = 6ft. 2 in.= $6\times12+2\text{ in.}=74\text{ in.}$

Let x be the random variable that represent the women's height.

z-score : $z=\dfrac{x-\mu}{\sigma}$

For x=57, we have

$z=\dfrac{57-63.2}{2.4}\approx-2.58$

For x=74, we have

$z=\dfrac{74-63.2}{2.4}\approx4.5$

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

$P(-2.58$

Hence, the percentage of women meeting the height requirement = 99.51%

8 0

4 years ago

Find the sum of the sequence 36 37 38 39 ... 109=

uysha [10]

It's an arithmetic sequence:

$a_1=36;\ a_2=37;\ a_3=38;\ ...\ ;\ a_{74}=109\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\a_1=36;\ n=74;\ a_{74}=109\\\\S_{74}=\dfrac{36+109}{2}\cdot74=\dfrac{145}{2}\cdot74=72.5\cdot74=5365$

8 0

3 years ago