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4 years ago

Robert and elena usually

Mathematics

1 answer:

ololo11 [35]4 years ago

7 0

They must make up their mind. Either they should never, or else they should always.

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52109 round to nearest ten

balandron [24]

Your answer is 52110

3 0

3 years ago

Find the equation for the linear function that passes through the points (−2,−5) and (4,4). State your equation with whole numbe

UNO [17]

Answer:

$y=\frac{3}{2} x-2$

Step-by-step explanation:

To find your slope using two points, use the slope formula.

$\frac{y2-y1}{x2-x1}$

Your y1 term is -5, your y2 term is 4.

Your x1 term is -2, your x2 term is 4.

$\frac{4-(-5)}{4-(-2)} \\\\\frac{9}{6} \\\\\frac{3}{2}$

Now that we have your slope, you can use the slope and one of your points in point-slope form to find your y-intercept.

$y-y1=m(x-x1)\\y-4=\frac{3}{2} (x-4)\\y-4=\frac{3}{2} x-6\\y=\frac{3}{2} x-2$

4 0

3 years ago

Help with #9<br> ASAP PLEASE.

yawa3891 [41]

you add the amount of people in each section that fits into the category. So, 11 people from 6-6:29 and 15 people from 6:30-6:59 and then 8 people from 7:30-7:59 so you get 34 people total

5 0

4 years ago

A point moves along the curve y = √ x in such a way that the y-component of the position of the point is increasing at a rate of

Eduardwww [97]

Answer:

The value of x component changes at a rate of $\frac{dx}{dt}=4\sqrt{x}$ units per second

Step-by-step explanation:

We are given that $y=x^{\frac{1}{2}}$

Differentiating on both sides with respect to time we get

$\frac{dy}{dt}=\frac{d\sqrt{x}}{dt}\\\\\frac{dy}{dt}=\frac{1}{2}x^{\frac{-1}{2}}(\frac{dx}{dt})\\\\\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}$

It is given that $\frac{dy}{dt}=2units/sec$

Solving for $\frac{dx}{dt}$ we get

$\frac{dx}{dt}=\frac{dy}{dt}\times 2\sqrt{x}\\\\\frac{dx}{dt}=4\sqrt{x}$

5 0

3 years ago

Math pls help????????????!!

9966 [12]

B (-3)/0 is undefined

6 0

3 years ago

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