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3 years ago

Help with #9 ASAP PLEASE.

Mathematics

1 answer:

yawa3891 [41]3 years ago

5 0

you add the amount of people in each section that fits into the category. So, 11 people from 6-6:29 and 15 people from 6:30-6:59 and then 8 people from 7:30-7:59 so you get 34 people total

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Find a number which in which added square<br>sum will be 72.

Tom [10]

Answer:

8.48528137424^2

Step-by-step explanation:

8.48528137424x8.48528137424

= 72

7 0

3 years ago

A school has a goal of getting at least 2000 boxtops. They have 872 so far. They have 8 days left to get it. At least how many d

True [87]

Answer:

School needs to collect at least 144 box tops each day to meet their goal.

Step-by-step explanation:

The total requirement of box tops = 2,000

The number of box tops they have already received = 872

So, the box tops left = Total number required- Number of tops received

=2,000 - 872

= 1,128 box tops are left so far.

Number of days left = 8

So, number of minimum tops needed each day = $\frac{\textrm{Total tops required}}{\textrm{Number of days left}}$

= $\frac{1128}{8} = 141$

Hence, they need to collect at least 144 box tops each day to meet their goal.

5 0

2 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

2 years ago

Find sin 2x,cos2x and tan2x,if tanx=-(3)/(4)and x terminates in quadrant IV

Montano1993 [528]

Answer:PLEASE HELP ME

Step-by-step explanation:

here can you guys please help me with this question.

I have been asking help from so many people but no one is nice enough to give it so im hoping that anyone over here can help me. this is the problem

Carl is standing at the base of a zip line which is 400 ft away from the base of the building that is connected to the top of a building. Standing 5.5 ft tall, he looks up to the top of the building at an angle of elevation of 25 degrees. A weight is released and travels down the zip line to his feet. How far did the weight travel? Round to nearest 10th of a foot and do not use units in your answer.

Please show work