<em>p</em> ² + 6 is even if <em>p</em> ² is even (the sum of two even numbers is even), and this happens only if <em>p</em> itself is even, i.e. if <em>p</em> = 2 since 2 is the only even prime.
All other primes <em>p</em> are odd, so <em>p</em> ² would be odd, and adding 6 would not change that (odd + even = odd).
Answer:
6
Step-by-step explanation:
Answer:
(2, - 4 )
Step-by-step explanation:
Given the 2 equations
x + 2y = - 6 → (1)
3x + y = 2 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the term in y
- 6x - 2y = - 4 → (3)
Add (1) and (3) term by term to eliminate y
- 5x = - 10 ( divide both sides by - 5 )
x = 2
Substitute x = 2 into either of the 2 equations and solve for y
Substituting into (1)
2 + 2y = - 6 ( subtract 2 from both sides )
2y = - 8 ( divide both sides by 2 )
y = - 4
Solution is (2, - 4 )
9514 1404 393
Answer:
36°
Step-by-step explanation:
The two halves of the bisected angle are congruent:
∠PQS = ∠RQS
3x = 2x +6
x = 6 . . . . . . . . . . subtract 2x
3x = 3(6) = 18 . . . . . half of angle PQR
∠PQR = 2(18°) = 36°
The length of the chord = 2(sqrt(10^2 - 6^2))
= 2(sqrt (100 - 36))
= 2(sqrt (64))
= 2(8)
= 16cm
The attached pic should put things into perspective hopefully
