The first answer is C. The information may be in a form that is difficult to use. And the second on is D. They must always be used with an equation.
The standard deviation of the frequency distribution is 5.54
<h3>How to determine standard deviation?</h3>
The table of values is given as:
x f(x)
0-3 13
4-7 13
8-11 10
12-15 11
16-19 0
20-23 3
Rewrite the table by calculating the class midpoints:
x f(x)
1.5 13
5.5 13
9.5 10
13.5 11
17.5 0
21.5 3
Start by calculating the mean using:

This gives

Evaluate

The standard deviation is then calculated as:

So, we have:

Evaluate

Solve

Hence, the standard deviation is 5.54
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Answer:

Step-by-step explanation:
Student 1 and 3.

Move the negative into the brackets,
positive becomes negative while two negatives make a positive.
Answer:
Step-by-step explanation:
T is at (1,2)
where x = 1 and y = 2
so if it's reflected over the x axis then it moves down wards. to (1, -2)