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Angelina_Jolie [31]
3 years ago
12

A carpenter has a board that is 10 feet long. He wants to make 6 table legs that are all the same length. What is the longest ea

ch leg can be?
Mathematics
2 answers:
boyakko [2]3 years ago
4 0
length\ of\ leg=\frac{10feet}{6}=1\frac{2}{3}feet\\\\
Each\ leg\ can\ be \ 1\frac{2}{3}feet\ long.
Marysya12 [62]3 years ago
3 0
If you divide 10 by 6 you get 1.6 repeatedly so if you turn it into a fraction which is 1 and 2/3

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What is the y - intercept of the equation y = 8x+4?<br> x-1
Tomtit [17]

Answer:

4

Step-by-step explanation:

y=8x+4

y=mx+b where m=slope and b=y-intercept

b=4

3 0
4 years ago
A textbook store sold a combined total of 289 sociology and math textbooks in a week. The number of math textbooks sold was 65 l
erica [24]

Answer:

Contradictrion

Step-by-step explanation:

First write an equation. If the total is 289, then that goes one the right side of the =. Sociology textbooks will be x. If there were 65 less than x, it will be 65-x. Lets set it up:

x + 65 -x =289

Then combine like terms.

65 = 289

There are no values of x that make the equation true. The input is a contradiction.

<u></u>

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8 0
3 years ago
Simplify: 18-|8+3(2+2)-4|
NeX [460]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
What is 31 in tens and ones
My name is Ann [436]
3 is in the tens and 1 is in the ones. To explain more easily... 30+1 is 31.<span />
5 0
3 years ago
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