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3 years ago

Simplify the product using the distributive property.

Mathematics

1 answer:

dimaraw [331]3 years ago

6 0

None of the above. The correct expansion is $9h^4-39h^2+42$ .

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If your answer is b<img src="https://tex.z-dn.net/?f=%5Cneq" id="TexFormula1" title="\neq" alt="\neq" align="absmiddle" class="l

adelina 88 [10]

Answer:

This means that b is not equal to -10.

3 0

2 years ago

A softball team is ordering pizza to eat after their tournament. They plan to order cheese pizzas that cost $6 each and four-top

Softa [21]

Answer:

Step-by-step explanation:

Well $1o each than 10×4=40 and 40 +6=46

7 0

3 years ago

Read 2 more answers

Factorise 15 x square - 6 X + 5 Y - 2 please answer me fast who answered will mark as brainleist

sweet-ann [11.9K]

Answer:

(3x+1)(5x-2)

Step-by-step explanation:

Given the expression

15x^2-6x+5x-2

Factorize;

3x(5x-2)+ 1(5x-2)

(3x+1)(5x-2)

Hence the factorized form is (3x+1)(5x-2)

4 0

2 years ago

$69 shoes with a 6% tax

nlexa [21]

6% of 69 is 4.14

So 69 + 4.14 = $73.14

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3 years ago

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Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select

Blizzard [7]

Answer:

Probability is: $\frac{\textbf{13}}{\textbf{51}}$

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $\frac{number \hspace{1mm} of \hspace{1mm} black \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards}$ $= \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}}$

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $\frac{number \hspace{1mm} of \hspace{1mm} red \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm}of \hspace{1mm} cards}$ $= \frac{26}{51}$

Now, the probability of both black and red card = $\frac{1}{2} \times \frac{26}{51}$

$= \frac{\textbf{13}}{\textbf{51}}$

Hence, the answer.

5 0

3 years ago