Answer: 55
Step-by-step explanation:
![\sqrt[3]{4x-4}=6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4x-4%7D%3D6)
Begin by cubing each side of the equation to get rid of the cubic root.
![(\sqrt[3]{4x-4})^3=(6)^3\\ 4x-4=216](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B4x-4%7D%29%5E3%3D%286%29%5E3%5C%5C%204x-4%3D216)
add 4

Divide by 4


The quadrilateral is a square
<h3>What are quadrilaterals?</h3>
Quadrilaterals are polygons, that have four sides and four corners
The coordinates are given as:
- A = (3, 5)
- B = (5, 2)
- C = (8, 4)
- D = (6, 7)
Start by calculating the adjacent side lengths using:

So, we have:




The side lengths are equal.
Hence, the quadrilateral is a square
Read more about quadrilaterals at:
brainly.com/question/5715879
If the function is f(x) = 6(0.4)x then the domain is ALL REAL NUMBERS and the range is ALL REAL NUMBERS!
Answer:
(2x -3)^2 = 0
Step-by-step explanation:
In this particular instance, the square is already complete. The rewrite is to show that.
(2x -3)^2 = 0
__
In the general case, ...
(ax +b)^2 = a^2x^2 +2abx +b^2
Comparing this form to the given left-side expression, we see that ...
a = 2, b = -3
So, the trinomial is already a perfect square trinomial.