Given,
We can use L'Hopital's Rule to get,
![\lim_{x}^{a}\dfrac{2}{3-\sqrt[3]{x}}](https://tex.z-dn.net/?f=%5Clim_%7Bx%7D%5E%7Ba%7D%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Bx%7D%7D)
Now plug in a,
![\boxed{\dfrac{2}{3-\sqrt[3]{a}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Ba%7D%7D%7D)
Hope this helps.
r3t40
No, you got the inequalities the wrong way.
In negative numbers, it is how much lower it is than 0. For example, -22 is 22 less than 0. And -2 is 2 less than 0. Here, -22 is actually less than -2 because it is farther below 0 than -2.
You can understand this better if you graph it on a number line.
So, -12 >-15. (-15 is 3 less than -12).
-1/3 >-1.
-2>-21.
((6)^3 (g^5)^3 (h)^3 + (-4)^3)
(216 x g^15 x h^3 - 64
216g^15h^3 - 64
Answer:
[(1.7×106)÷(2.63×105)]+7.33
=7.9825439073
I HOPE IT HELP YOU
