Solve the system algebraically. Check your work.

Mathematics

1 answer:

Luden [163]3 years ago

8 0

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10 (1)

And 3x+2y=63x+2y=6 (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30 (3)

15x+10y=3015x+10y=30 (4)

Now subtract (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

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