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kramer
3 years ago
11

How do I solve this equation??(6g^5h-4)^3

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0
((6)^3 (g^5)^3 (h)^3 + (-4)^3)
(216 x g^15 x h^3 - 64
216g^15h^3 - 64
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Last month maria purchased a new cell phone for $500. the store manager told her that her cell phone would depreciate by 70% eve
Aleksandr-060686 [28]

We have been given that last month Maria purchased a new cell phone for $500. The store manager told her that her cell phone would depreciate by 70% every 6 months.

We know that an exponential function is in form y=a\cdot (1-r)^x, where,

y = Final value,

a = Initial value,

r = Decay rate in decimal form,

x = Time in years.

Let us convert 70\% into decimal form.

70\%=\frac{70}{100}=0.70

Initial value of car is 500, so a=500.

Since value of phone depreciates every  months, so value of phone will depreciate twice in a year.

Upon substituting our given values in exponential decay function, we will get:

V=500(1-0.70)^{2x}

To find the value of phone after 2 years, we will substitute x=2 in our equation.

V=500(1-0.70)^{2(\cdot 2)}

V=500(1-0.70)^{4}

Therefore, option D is the correct choice.

Let us simplify our equation.

V=500(0.30)^{4}

Therefore, option B is correct as well.

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3 years ago
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