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mamaluj [8]
3 years ago
5

Simplify the expression by arranging the steps in sequence based on the order of operations 1/6(30x+24)-1/7(63-7×)

Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

6x-5

Step-by-step explanation:

We apply distributive property to get rid of the first parenthesis, by multiplying each term inside by the factor 1/6:

\frac{1}{6} (30x+24)-\frac{1}{7} (63-7x)\\\frac{30}{6} x+\frac{24}{6} -\frac{1}{7} (63-7x)\\5x+4-\frac{1}{7} (63-7x)

now we get rid of the second parenthesis by multiplying the factor "-\frac{1}{7}" times each of the terms inside the parenthesis (notice here that this factor is negative , so it will flip the signs of the terms it multiplies):

5x+4-\frac{1}{7} (63-7x)\\5x+4-\frac{63}{7} +\frac{7}{7} x\\5x+4-9+x

Next we combine like terms:

5x+4-9+x\\5x+x+4-9\\6x-5

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If the slope is 6 and the point is (4,-7), point-slope form is
Brrunno [24]

Step-by-step explanation:

y+7=6(x-4)

y+7=6x-24

y=6x-31

5 0
2 years ago
Is-2 an integer or rational #
Kruka [31]

Answer:

hello your answer is rational  −2 is a rational number because we can express it as a ratio of two whole numbers.

Step-by-step explanation:

hope i helped

6 0
3 years ago
Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-
nekit [7.7K]

Complete Question

Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-type crashes. Red-Light-Running System A resulted in 60% angle crashes over a sample of 720 total crashes. Red-Light-Running System B resulted in 52% angle crashes over a sample of 680 total crashes. Was there a difference between the proportions of angle crashes between the two red-light-running systems installed? Use an alpha of 0.10.

Answer:

Yes there is a difference between the proportions of angle crashes between the two red-light-running systems installed

Step-by-step explanation:

From the question we are told that

   The first sample  proportion  is  \r  p_ 1 =  0.60

   The  second sample proportion is  p_2 =  0.52

    The first sample size is  n_1 =  720

     The second sample size is  n_2  =  680

     The  level of significance is  \alpha = 0.10

     

The null hypothesis is H_o  :  \r p_1 -  \r p_2 =  0

The  alternative hypothesis is  H_a :  \r p_1 - \r p_2 \ne  0

Generally the pooled proportion is mathematically represented as

       p_p =  \frac{(\r p_1 *  n_1 ) + (\r p_2 * n_2)}{n_1 + n_2 }

=>     p_p =  \frac{(0.6 *  720) + ( 0.52 * 680)}{720 +680 }

=>    p_p  = 0.56

 Generally the test statistics is evaluated as        

       t  =  \frac{ ( \r p_1  - \r p_2 )  - 0 }{ \sqrt{ (p_p  (1- p_p)  *  [ \frac{1}{n_1 } +  \frac{1}{n_2 }  ])} }

        t  =  \frac{ (0.60   - 0.52 )  - 0 }{ \sqrt{ (0.56  (1- 0.56)  *  [ \frac{1}{720} +  \frac{1}{680 }  ])} }    

       t  =  3.0

The  p-value obtained from the z-table is  

      p-value  =  P(Z> t ) =  0.0013499

From the question we see that p-value  <  \alpha so the null hypothesis is rejected

 Hence we can conclude that there is a difference between the proportions

         

3 0
3 years ago
I will give brainliest to whoever helps me with this question. Also, if you could please explain to me how you solved it I would
kow [346]

64 yards is the answer

As The proportion of corresponding sides are equal hence X=64 yds

mark me the Brainliest

8 0
2 years ago
Read 2 more answers
The equation x2 − 9 = 0 has real solution(s).
tatiyna

Answer:

The roots are real and unequal (3, -3)

Step-by-step explanation:

x²-9=0

ax²+bx+c=0

Comparing we get,

a= 1

b= 0

c = -9

Determinant: b²-4ac

= 0² - 4(1)(-9)

= 36>0

D > 0

Therefore, the equation has real and unequal roots.

Algebraic identity:

x² - a² = (x-a)(x+a)

Using this identity

x²-9 = (x+3)(x-3)

Roots are 3 and -3 which are real and not equal to each other

Hope this answer helps you ..

6 0
3 years ago
Read 2 more answers
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