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larisa [96]
2 years ago
10

I need help Thank you i will give brinalist

Mathematics
2 answers:
dangina [55]2 years ago
8 0

Answer:

C

Step-by-step explanation:

The scatter plot doesn't look linear at all. Therefore, there is no association to game attendance and games won.

Luba_88 [7]2 years ago
7 0

Answer:

the answer to this is c no association.

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Multiply 5/8⋅4/5.<br> Simplify the answer, if possible. <br> 9/13 <br> 1 1/740 <br> 20/40 <br> 1/2
Fofino [41]

Answer:

1/2

The LCD is 40, so find the rest using expressions and comparisons.

  • 8 × 5 = 40

5/8 × 4/5 = 20/40

  20 ÷ 20 = 1

  40 ÷ 20 = 2

6 0
2 years ago
9. Find the sum of the first 6 terms of the sequence: –3, 1, 5, 9, . . . options: A) 25 B) 48 C) 42
ZanzabumX [31]

Answer:

C. 42.

Step-by-step explanation:

This is an arithmetic sequence with common difference d = 4 and first term a = -3.

Sum of n terms = (n/2)[2a + (n - 1)d]

Sum of  six terms = (6/2)[2(-3) + (6 - 1)4]

= 3 * (-6 + 20)

= 42.

5 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (4, -7) and has a
otez555 [7]

Answer:

I think that some information is missing? what is the slope?

If you are trying to say that there is NO SLOPE then the

answer is " x = 4 "

Step-by-step explanation:

8 0
3 years ago
Tom, Mary and Bill are aged 10,12 and 15 years respectively. They share 259 euros in the same ratio as their ages. Find how much
tigry1 [53]

Answer:

70 , 84 , 105

Step-by-step explanation:

sum their ages , 10 + 12 + 15 = 37

divide the amount by this sum to find the value of one part of the ratio.

259 ÷ 37 = 7 ← value of 1 part of the ratio , then

10 parts = 10 × 7 = 70 euros ← Tom's share

12 parts = 12 × 7 = 84 euros ← Mary's share

15 parts = 15 × 7 = 105 euros ← Bill's share

7 0
2 years ago
I need the answer to this❤️
KATRIN_1 [288]

Answer:

5/2x, 5/2 y

Step-by-step explanation:

An enlargement means the scale factor must be greater than one

The only choice with a scale factor greater than one is 5/2x, 5/2 y

5 0
3 years ago
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