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RideAnS [48]
2 years ago
11

What privacy risks do new technologies present, and how do we decide if they're worth it?

Computers and Technology
1 answer:
vredina [299]2 years ago
6 0

Answer:

Los riesgos de las nuevas tecnologías se multiplican a medida que nos hacemos dependientes de ellas. También lo hacen a medida que sustituyen a otras formas de contacto social más cercanas

Los riesgos de las nuevas tecnologías son grandes desconocidos. El mal uso de las redes sociales y de Internet en los ordenadores y en el teléfono móvil, entre otros factores, supone un peligro real para todos los estratos de población, pero en especial para los más jóvenes. Pensemos, ¿realmente somos conscientes de los riesgos que suponen las nuevas tecnologías? ¿Sabemos cómo utilizarlas para no ponernos en riesgo?

Cabe destacar que las denominadas nuevas tecnologías de la información y de la comunicación (TICs) son un distintivo de la época actual y se han convertido en herramientas esenciales en las diferentes áreas de la vida. Esto es, para el área académica, laboral, social, de ocio…

En la mayoría de los ámbitos están presentes las TICS, pues incluyen las diferentes herramientas con las que nos manejamos hoy en día: servicios de contacto electrónico (e-mails, servicios de mensajería instantánea, chats), los teléfonos móviles, tablets y ordenadores, las plataformas online de difusión de contenidos, las redes sociales, entre otros..

Explanation:

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Develop a CPP program to test is an array conforms heap ordered binary tree. This program read data from cin (console) and gives
mafiozo [28]

Answer:

Following are the code to this question:

#include<iostream>//import header file

using namespace std;

int main()//defining main method

{

int ar[7];//defining 1_D array that stores value      

int i,x=0,l1=1,j; //defining integer variable

for(i=0;i<7;i++)//defining for loop for input value from user ends  

{

cout<<"Enter a Number: ";//print message

cin>>ar[i];//input value in array

if(l1<=2 && i>0)//using if block that checks the array values  

{

x++;//increment the value of x by 1  

}

if(l1>2 && i>0)//using if block that checks the array values  

{

l1=l1-2;//using l1 variable that decrases the l1 value by 2  

}

j=i-x;//using j variable that holds the index of the root of the subtree

if(i>0 && ar[j]>ar[i])// use if block that checks heap condition  

{

l1++; //increment the value of l1 variable

}

if(i>0 && ar[j]<ar[i])// using the if block that violate the heap rule  

{

cout<<ar[i]<<" "<<"Violate the heap";//print message with value

break;//using break keyword  

}

}

return 0;

}

Output:

1)

Enter a Number: -15

Enter a Number: -5

-5 Violate the heap

2)

Enter a Number: 45

Enter a Number: 0

Enter a Number: 55

55 Violate the heap

Explanation:

  • In the above-given C++ language code, an array "ar" and other integer variables " i,x,l1, j" is declared, in which "i" variable used in the loop for input values from the user end.
  • In this loop two, if block is defined, that checks the array values and in the first, if the block it will increment the value of x, and in the second if the block, it will decrease the l1 value by 2.
  • In the next step, j variable is used that is the index of the root of the subtree. In the next step, another if block is used, that checks heap condition, that increment the value of l1 variable. In the, if block it violate the heap rule and print its values.
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