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Grace [21]
3 years ago
6

Write a program that prompts the user to enter a four-digit integer and displays the number in reverse order. Here is a sample r

un:
Enter an integer: 5213

3

1

2

5
Computers and Technology
1 answer:
iVinArrow [24]3 years ago
7 0

Following are the code that is written in c language

#include <stdio.h>

int main() // main function

{

int n1,t; // declaring variable

printf(" Enter an integer :");

scanf("%d",&n1); // taking input

while(n1>0) // iterating over the loop untill the value of n is greater then 0

 {

t=n1%10;

printf("%d",t);

printf("\n");

n1=n1/10;

}

return 0;

}

Explanation:

we taking an integer value n1 and iterating over the loop untill n1>0

suppose n1=1234

then  t=n%10;

means t=1234%10

as % holds reminder means t=4

then print the value of t means print 4

and n1 becomes 123 which is > 0  again condition is checking and same process is follow untill n1>0

output

Enter an integer: 5213

3

1

2

5

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   string Score, Rank;

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   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

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   stringstream tream(Rank);

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   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

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<em>    sstream>>testScore;</em>

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

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If testScore >= 90

<em>    if (testScore >= 90){</em>

If classRank >=25

<em>        if(classRank >=25){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    } ---</em>

If testScore >= 80

<em>    else if(testScore >= 80){</em>

If classRank >=50

<em>        if(classRank >=50){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

If testScore >= 70

<em>    else if(testScore >= 70){</em>

If classRank >=75

<em>        if(classRank >=75){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

For testScore less than 70

<em>    else{cout<<"Reject";}</em>

<em />

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