Answer:
Train A = 214
Train B = 86
Step-by-step explanation:
a + b = 300
a - b = 128
a + b = 300
a = 128 + b
(128 + b) + b = 300
128 + b + b = 300
128 + 2b = 300
2b = 300 - 128
2b = 172
b = 172 ÷ 2
b = 86
a = 128 + b
a = 128 + (86)
a = 214
A rectangle has two dimensions, width and length, and the area of it is their product.
since we know its area is 3x²-11x-4, then the two factors from that trinomial are the likely width and length, namely (3x + 1) (x - 4).
you can check them with FOIL.
Answer:
Please check the explanation.
Step-by-step explanation:
Given the vector
v = 6i + 2√3j
The Magnitude of a vector:
![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D)
The Direction of a vector:
tan Ф = y/x
y=2√3
x = 6
tan Ф = y/x
= 2√3 / 6
= √3 / 3
It would be, 6.72/3 = $2.24
Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
