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Kay [80]
3 years ago
11

A theater is presenting a program on drinking and driving for students and their parents or other responsible adults. The procee

ds will be donated to a local alcohol information center. Admission is for adults and for students.​ However, this situation has two​ constraints: The theater can hold no more than people and for every two​ adults, there must be at least one student. How many adults and students should attend to raise the maximum amount of​ money?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0
There should be 2 kids
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Given that tan 0=-4/7 , and 270 degrees <0<360 degrees , what is the exact value of sec0?
Elanso [62]
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6 0
3 years ago
The diagram shows a circle and an equilateral triangle. One side of the equilateral triangle is a diameter of the circle. The ci
Lemur [1.5K]

Answer:

Area = 101.4 cm^2 (3 S.F)

Step-by-step explanation:

Diameter of circle (D) = one side of the equilateral ∆

Circumference of the circle = πD = 48 cm

Thus:

πD = 48

Divide both sides by π

D = \frac{48}{\pi} = 15.3 cm (approximated to nearest tenth)

Since all sides an equilateral ∆ are equal, therefore, and the diameter, D, of the circle given is the same as the length of one side of the ∆, therefore, all sides of the equilateral triangle would be 15.3 cm.

Recall that the area of a triangle can be found if we know lengths of the two sides of the ∆ and the measure of the included angle between both sides.

Since an equilateral ∆ has equal angles, each measuring 60°, then we already have all the information needed to calculate the area of the ∆.

Thus:

Length of the two sides = 15.3 cm and

15.3 cm

Included angle = 60°

Use the following formula:

Area = \frac{1}{2}ab \times Sin(C)

Where,

a = 15.3 cm

b = 15.3 cm

C = 60°

Plug the values into the formula to find the area.

Area = \frac{1}{2} \times 15.3 \times  15.3 \times Sin(60)

Area = \frac{1 \times 15.3 \times  15.3 \times Sin(60)}{2}

Area = 101.4 cm^2 (3 S.F)

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3 years ago
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Find the average value of the function g(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7Blnx%7D%7Bx%7D" id="TexFormula1" title=
aleksley [76]

Answer:

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<u>Average Value of a Function</u>

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