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Mrac [35]
3 years ago
12

A limited-edition poster increases in value each year. After 1 year, the poster is worth $20.70. After 2 years, it is worth $23.

81. Which equation can be used to find the value, y, after x years? (Round money values to the nearest penny.) y = 18(1.15)x y = 18(0.15)x y = 20.7(1.15)x y = 20.7(0.15)x
Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0
The answer is A ......
MAXImum [283]3 years ago
7 0
First we want to find the amount that will be worth 20.7 after one year and 23.81 after two years
So I assume that
Y =p (1.15)^x
Where
Y 20.7
P ?
X 1 year
20.7=p (1.15)^1
Solve for p
P=20.7÷1.15
P=18

The answer is
Y=18 (1.15)^x

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For b) you already have two possibilities, since you have the intercepts. 
<span>(20358, 0) and (0,15834) are two possible points, although not very likely. </span>

<span>Solve for y: y= (-7/9)x + 15834 </span>

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