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Mrac [35]
3 years ago
12

A limited-edition poster increases in value each year. After 1 year, the poster is worth $20.70. After 2 years, it is worth $23.

81. Which equation can be used to find the value, y, after x years? (Round money values to the nearest penny.) y = 18(1.15)x y = 18(0.15)x y = 20.7(1.15)x y = 20.7(0.15)x
Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0
The answer is A ......
MAXImum [283]3 years ago
7 0
First we want to find the amount that will be worth 20.7 after one year and 23.81 after two years
So I assume that
Y =p (1.15)^x
Where
Y 20.7
P ?
X 1 year
20.7=p (1.15)^1
Solve for p
P=20.7÷1.15
P=18

The answer is
Y=18 (1.15)^x

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= -3.5 / 1

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6 0
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Read 2 more answers
If x^2=64 and x is positive, what is the value of <br><img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7Bx%7D%20" id="TexFormula1"
guapka [62]
X²=64
√x²=√64=8
x=8 (positive)
∛x=∛8=∛(2)³=2
∛x=2
4 0
3 years ago
How to solve number 4
s2008m [1.1K]
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²

Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².

Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²

To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157

The area of shaded region is 157 cm²
4 0
3 years ago
In which situation below would you want to use the Explicit Formula instead of the Recursive Formula?
Luden [163]

9514 1404 393

Answer:

  all of them, possibly excepting the 4th term

Step-by-step explanation:

The recursive formula is good if you have terms near the one of interest. It might be used for the 4th term, but that would require that you compute the three previous terms:

  7, 5, 3, 1 . . . . requires 3 subtractions

It can be about as easy to calculate ...

  a4 = 7 -2(3) = 1 . . . . requires two* subtractions and a multiplication

__

However, for the 7th, 11th, and 106th terms, it is impractical to list all previous terms. The explicit formula is a better choice.

A.  a4 = 7 -2(3) = 1

B.  a7 = -1 +10(6) = 59

C.  a106 = 2 +5(105) = 527

D.  a11 = -3 +4(10) = 37

_____

* The explicit formula is ...

  an = a1 +d(n -1)

The operations identified in this formula (in the order required by the Order of Operations) are subtraction, multiplication, and addition. For a negative common difference, that amounts to two subtractions and a multiplication.

For manual evaluation, the work involved in using the recursive or explicit formulas for the 4th term is about the same, if the arithmetic is easily done mentally (as here).

5 0
3 years ago
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