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3 years ago

WILL RATE BRAINLIEST PLZ HELP MUST EXPLAIN THO

Mathematics

1 answer:

madreJ [45]3 years ago

8 0

Answer:

A -- base 3, height 4
B -- base 4, height 4
C -- base 3, height 3
D -- base 3, height 5

Step-by-step explanation:

A sort of straightforward way to approach this is to define base and height variables for each of the figures: ba, ha, bb, hb, bc, hc, bd, hd. Then the statements can be used to make equations in these variables.

0. hc = bc . . . . figure C is a square

1. ba = bd

2. ba = bb -1

3. hc = ba

4. hb = ha = bb

5. hc·bc = 9

6. (1/2)ha·ba +(1/2)hb·bb +hc·bc+hd·bd = 38

Using equations 0 and 5, we find ...

hc² = 9 ⇒ hc = 3

From equation 3, ...

ba = 3

From equation 2, ...

3 = bb -1 ⇒ bb = 4

From equation 1, ...

bd = 3

From equation 4, ...

ha = hb = 4

Filling in the values we know in equation 6, we get ...

(1/2)(4)(3) +(1/2)(4)(4) +9 +hd(3) = 38

23 +3hd = 38

hd = 15/3 = 5

The dimensions are:

A -- base 3, height 4
B -- base 4, height 4
C -- base 3, height 3
D -- base 3, height 5

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marishachu [46]

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Explanation:

The given equation is $y=x^2+2x-1$ .

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The given equation can be written as $y=(x^2+2x)-1$ .

To make the perfect square we can add or subtract $(\frac{b}{2a})^2$ in the given equation. Where, a is coefficient of $x^2$ and b is coefficient of x. In the parenthesis the coefficient of $x^2$ is 1 and coefficient of x is 2.