Answer:
a) 5units
b) (4.5, 4)
Step-by-step explanation:
Let the coordinate of P and Q be P(3, 2) and Q(6, 6)
PQ can be gotten using the distance formula;
PQ =√(6-2)²+(6-3)²
PQ = √4²+3²
PQ =√16+9
PQ =√25
PQ = 5units
Midpoint M is expressed as;
M(X, Y) = {(x1+x2)/2, y1+y2/2}
X = x1+x2/2
X = 3+6/2
X= 9/2
X = 4.5
Similarly;
Y = y1+y2/2
Y = 2+6/2
Y = 8/2
Y = 4
Hence the midpoint of PQ is (4.5, 4)
Answer:
Group B has the higher median by 0.5 inches. The IQR for Group A is smaller. IQR for Group B is 2 inches.
Number 4 is 66
Number 5 Iseconds 5.32
Answer: 10%
Step-by-step explanation:
The difference between his estimated and actual distance is 15 - 13.5 = 1.5
The percentage of error is the difference divided by the actual value.
1.5÷15 = 0.10
Converted to a percentage, it is 10%
Answer: area is 286.16 ft²
Step-by-step explanation:
Length of the sand pit is 29.2 feet and the width is 9.8 feet.
L= 29.2 ft
W = 9.8 ft
To find out the area, all we have to do is multiply the lenght by the width:
And do not forget that to calculate the area, all units must be the same and for the area, it is always the unit squared, in this case, feet square or simply (ft²).
A = l*w
A = 29.2 * 9.8 = 286.16 ft²
