Answer:
Slope intercept form:- An equation of line is in the form of y =mx +b .....[1] ; where m is the slope and b is the y-intercept.
Consider any two point from the table i.e,
(1, -2) and (2 , -6)
Calculate first slope of these points:
Slope(m) = ![\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
then;
![m=\frac{-6+2}{2-1}=\frac{-4}{1}=-4](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-6%2B2%7D%7B2-1%7D%3D%5Cfrac%7B-4%7D%7B1%7D%3D-4)
then; substitute the value of m in [1]
Equation of line is;
......[2]
Now, substitute any coordinate point from the table i.e (3 , -10) in [2] to solve for b;
-10 = -4(3) +b
-10 = -12 +b
Add both sides 12 we get;
-10 + 12 = -12 +b +12
Simplify:
2 = b
Equation of line is; y = -4x+2
Therefore, the slope intercept form of the function describe by the given table is;
y = -4x +2