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agasfer [191]
3 years ago
5

Which statement is true about the equation fraction 4 over 5z = fraction 1 over 5z − 4 + 6?

Mathematics
1 answer:
Westkost [7]3 years ago
7 0
Assuming your question asks for what values of z satisfy
\frac{4}{5z} = \frac{1}{5z} -4+6, we start by simplifying the terms  -4+6. This will get us \frac{4}{5z} = \frac{1}{5z} +2
Next, we can multiply both sides by 5z, to get 4=1+10z Subtract 1 on both sides to get 3=10z Finally, we isolate z by dividing both sides by 10. 
z=\frac{3}{10}

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STALIN [3.7K]

Answer:

-75

Step-by-step explanation:

f(-10) = 7(-10) - 5

f(-10) = -70 - 5

f(-10) = -75

8 0
3 years ago
Please help ASAP<br><br> If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x)<br> b.) (gof) (-2)
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\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}


\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}

______


\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}

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If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559


\large\textsf{I hope this helps. :-)}


Tags: <em>composite function composition evaluate algebra</em>

7 0
3 years ago
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elena-14-01-66 [18.8K]

Answer:

-9

Step-by-step explanation:

an integer is a whole number!

4 0
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lesantik [10]

Sorry i dont know this one

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3 years ago
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Answer:

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Step-by-step explanation:

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8 0
2 years ago
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