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agasfer [191]
3 years ago
5

Which statement is true about the equation fraction 4 over 5z = fraction 1 over 5z − 4 + 6?

Mathematics
1 answer:
Westkost [7]3 years ago
7 0
Assuming your question asks for what values of z satisfy
\frac{4}{5z} = \frac{1}{5z} -4+6, we start by simplifying the terms  -4+6. This will get us \frac{4}{5z} = \frac{1}{5z} +2
Next, we can multiply both sides by 5z, to get 4=1+10z Subtract 1 on both sides to get 3=10z Finally, we isolate z by dividing both sides by 10. 
z=\frac{3}{10}

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Answer:

Idhduen

Step-by-step explanation:

6 0
3 years ago
Find the lenght of side BC. give your answer to 3 significant figures
Serga [27]

Answer:

BC ≈ 19.4 cm

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos71° = \frac{adjacent}{hypotenuse} = \frac{AB}{BC} = \frac{6.3}{BC} ( multiply both sides by BC )

BC × cos71° = 6.3 ( divide both sides by cos71° )

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3 0
4 years ago
MARKIG BRAINLIEST ..
Rainbow [258]

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Step-by-step explanation:

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7 0
3 years ago
The first and last terms of a 52-term arithmetic series are listed in the table. What is the sum of the series?
inna [77]

sum = x(n+1)/2

where x is the number of the term ( in this case 52)

 n is the last number in the series( which is not given in the problem)

6 0
3 years ago
Solve each problem and show the work for each one.
Cerrena [4.2K]

Answer:

Solve by factoring.

1. 2x^2+9x+26=-4x+5

2x²+9x+4x+26-5=0

2x²+13x+21=0

doing middle term factorization

2x²+7x+6x+21=0

x(2x+7)+3(2x+7)=0

<u>(</u><u>2</u><u>x</u><u>+</u><u>7</u><u>)</u><u>(</u><u>x</u><u>+</u><u>3</u><u>)</u><u>=</u><u>0</u>

<u>either</u>

<u>x</u><u>=</u><u>-</u><u>7</u><u>/</u><u>2</u>

<u>or</u>

<u>x</u><u>=</u><u>-</u><u>3</u><u>.</u>

2.

3x^2-6x-4=0

comparing above equation with ax²+bx+c=0

we get

a=3

b=-6

c=-4

By using quadratic equation

x=\frac{ - b±\sqrt{ {b}^{2} - 4ac } }{2a}

Substituting value

x=\frac{ 6±\sqrt{ {-6}^{2} - 4*3*-4 }}{2*-4}

x=\frac{ 6±\sqrt{ {84}}}{-8}

x=\frac{ 6±2\sqrt{ {21}}}{-8}

-8x=6±2√21

taking positive

-8x=6+2√21

x=\frac{6+2√21}{-8}

x=-\frac{3+√21}{4}

taking negative

-8x=6-2√21

x=\frac{6-2√21}{-8}

x=-\frac{3-√21}{4}

8 0
3 years ago
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