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3 years ago

Simplify: 5x+9y-7x+2-5y-7x+2-3x please help

2 answers:

6 0

So you add all the like terms.......i.e numbers with same variable
so,
5x+9y-7x+2-5y-7x+2-3x
=(5-7-7-3)x+(9-5)y+2+2
=-12x+4y+4

kobusy [5.1K]3 years ago

6 0

5x+9y-7x+2-5y-7x+2-3x=(5x-7x-7x-3x)+(9y-5y)+(2+2)=8x+2y+4

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A number and it's absolute value are equal. If you subtract 2 from the number, the new number and it's absolute value are not eq

yaroslaw [1]

This means that the number is positive.

The absolute value is the distance away from 0 the number is.

So 1's absolute value would be 1, yet -5's absolute value would be 5.

So the number that's equal to its absolute value is positive, and the one that's not is negative.

So if you subtract 2 from the positive number, it must turn negative.

So 1 is a number that satisfies these conditions.

6 0

3 years ago

The inequality below compares two rational numbers. -8/18 > -17/27

astraxan [27]

Answer:

I have provided it below

Step-by-step explanation:

- 8/18 > - 17/27

- 0.444444 > 0.62963

So this inequality is TRUE

Hope this helps!!

6 0

3 years ago

A pharmaticeutical company is making a new medicine capsule shaped like a cylinder with a half sphere at each end. The

DerKrebs [107]

Answer:

339.12 cubic millimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The volume of the figure is equal to the volume of the two hemispheres (one sphere) plus the volume of the cylinder

step 1

Find the volume of the cylinder

The volume is given by

$V=Bh$

where

B is the area of the base of cylinder

h is the height of cylinder

we have

$B=\pi r^{2}$

we have

$h=8\ mm$

$r=6/2=3\ mm$ ----> the radius is half the diameter

$B=(3.14)(3)^{2}$

$B=28.26\ mm^2$

substitute

$V=(28.26)(8)=226.08\ mm^3$

step 2

Find the volume of the sphere

The volume is given by

$V=\frac{4}{3}\pi r^{3}$

we have

$r=6/2=3\ mm$ ----> the radius is half the diameter

substitute

$V=\frac{4}{3}(3.14)(3)^{3}=113.04\ mm^3$

step 3

Adds the volumes

$226.08+113.04=339.12\ mm^3$

6 0

3 years ago

Write 3.242424... as a mixed number

Marysya12 [62]

Answer:

3 8/33

Step-by-step explanation:

5 0

3 years ago

50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n

irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0

3 years ago