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tigry1 [53]
3 years ago
15

Write the next two terms in the pattern 9,27,81,243

Mathematics
2 answers:
Basile [38]3 years ago
8 0

Answer:

729, 2,187, 6,561‬

Hope this helps!

Leni [432]3 years ago
4 0

Answer:

729, 2187

Step-by-step explanation:

Note the common ratio between consecutive terms, that is

27 ÷ 9 = 81 ÷ 27 = 243 ÷ 81 = 3

Thus to obtain the next term in the sequence multiply the previous term by 3

243 × 3 = 729

729 × 3 = 2187

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What is the expression of “the sum of n and the sum of 8 and 6?”
trapecia [35]

Answer:

n+8+6

Sum means = and and means + so n+8+6

7 0
3 years ago
Determine the area of each polygon <br><br> Help me please
Wewaii [24]
The area of the polygon is 52.5cm^2.
Area of triangle + Area of rectangle
(b)(h)/2 + (b)(h)
(5)(5)/2 + (8)(5)
25/2 + 40
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6 0
3 years ago
Find the median, first quartile, third quartile, and interquartile range of the data.
lana66690 [7]

Given:

The data set is:

68, 74, 67, 72, 63, 70, 78, 64, 76

To find:

The median, first quartile, third quartile, and interquartile range of the data.

Solution:

We have,

68, 74, 67, 72, 63, 70, 78, 64, 76

Arrange the given data in ascending order.

63, 64, 67, 68, 70, 72, 74, 76, 78

Now divide the data in two equal parts.

(63, 64, 67, 68), 70, (72, 74, 76, 78)

So, the median of the given data set is 70.

Divide each parenthesis in two equal parts.

(63, 64), (67, 68), 70, (72, 74), (76, 78)

Now, the first quartile is:

Q_1=\dfrac{64+67}{2}

Q_1=\dfrac{131}{2}

Q_1=65.5

The third quartile is:

Q_3=\dfrac{74+76}{2}

Q_3=\dfrac{150}{2}

Q_3=75

The interquartile range (IQR) is the difference between third quartile and first quartile.

IQR=75-65.5

IQR=9.5

Therefore, median is 70, first quartile is 65.5, third quartile is 75 and the interquartile range is 9.5.

7 0
3 years ago
PLEASE HELP!!!!!!!!!!
bija089 [108]
The answer is the first one
5 0
3 years ago
What is one-sixth of $5.28?
liubo4ka [24]

I think that it is $0.88

6 0
3 years ago
Read 2 more answers
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