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Ksivusya [100]
3 years ago
7

Simplify (1/2x^2y)^5

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

Start with

\left(\dfrac{1}{2}x^2y\right)^5

We have to raise all terms to the fifth power:

\left(\dfrac{1}{2}x^2y\right)^5 = \left(\dfrac{1}{2}\right)^5\cdot (x^2)^5\cdot y^5

Recall the law

(a^b)^c=a^{bc}

to conclude that

\left(\dfrac{1}{2}x^2y\right)^5 = \dfrac{1}{2^5}x^{10}y^5=\dfrac{1}{32}x^{10}y^5

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Step-by-step explanation:

18+14=32

32 is the total

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Find an equation perpendicular to x=1 and passing through (8,-9)
valina [46]

Answer:

y=-9

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We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).

Note that x=1 is a <em>vertical line </em>since x is 1 no matter what y is.

This means that if our new line is perpendicular to the old, then it must be a <em>horizontal line</em>.

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Step-by-step explanation:

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Find the slope of the line through the given points (4,-2),(-1,8)
nikklg [1K]

Answer:

\displaystyle m=-2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (4, -2)

Point (-1, 8)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

  1. Substitute in points [Slope Formula]:                                                             \displaystyle m=\frac{8+2}{-1-4}
  2. [Fraction] Add/Subtract:                                                                                  \displaystyle m=\frac{10}{-5}
  3. [Fraction] Divide:                                                                                                 \displaystyle m=-2<em><u> </u></em>
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2 years ago
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I'm guessing that is division?

4x^2/9z^3
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