Answer:
4
4+4-4=4 im not sure actually D:
Answer:
(5,19) lies on the graph of the transformed function y = f(1/5x)
Step-by-step explanation:
Suppose (1,19) is on the graph of y = f (x)
the graph of the transformed function y = f(1/5x)

1/5 is multiplied with x in f(x)
1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5
To make horizontal stretch we change the point
f(x)=f(bx) then (x,y) --->( x/b,y)
We divide the x coordinate by the fraction 1/5
(1,19) ----> 
So (5,19) lies on the graph of the transformed function y = f(1/5x)
The percentage of the semicircle shaded section is approximately 23,606 %.
The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

(1)
Where:
- Area of the half cross, in square centimeters.
- Area of the semicircle, in square centimeters.
- Percentage of the shaded section of the semicircle.
And the percentage of the shaded section is:
![r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100](https://tex.z-dn.net/?f=r%20%3D%20%5Cleft%5B1-%5Cfrac%7B4%20%5Ccdot%20%282%5C%2Ccm%29%5E%7B2%7D%2B4%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5Ccdot%20%282%5C%2Ccm%29%5E%7B2%7D%7D%7B0.5%5Ccdot%20%5Cpi%5Ccdot%20%2816%5C%2Ccm%5E%7B2%7D%2B4%5C%2Ccm%5E%7B2%7D%29%7D%20%5Cright%5D%5Ctimes%20100)

The percentage of the semicircle shaded section is approximately 23,606 %.
We kindly invite to check this question on percentages: brainly.com/question/15469506
Answer:
49°, 59°, 72°
Step-by-step explanation:
Angles of a triangle must add up to 180°.
49° + 59° + 72° = 180°
28° + 58° + 62° = 148°
39° + 89° + 108° = 236°
45° + 70° + 85° = 200°
Only the first set could represent the interior angles of a triangle.