A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say
x.
The lateral faces are equilateral triangles of side length
x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find
x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:

thus,

thus:

(cm^2)
but

is exactly the base area, since the base is a square of sidelength =
x cm.
So, the total surface area = base area + lateral area =

cm^2
Answer:

cm^2
Answer:
[-16,-4]
Step-by-step explanation:
We are given that

Domain=[-2,1]
We have to find the set of range values of f(x).
Substitute x=-2


Substitute x=1

Range of f(x)=[-16,-4]
Hence, the set of range values of f(x)
[-16,-4]
Answer:
first you have to add
Step-by-step explanation:
First you would want to find the length of one eraser and then multiply that by 2. To find the length of one you take the total length or all of them and divide it my the total number of them. 29 1/4 is 117/4.
(117/4) / 13 Dividing by something is the same as multiplying by the opposite.
117/4 × 1/13 = 117/52
Now you multiply by 2.
117/52 * 2/1 Cross simplify
117/26 * 1/1
117/26 inches or 4 1/2 inches.
Answer:
-7, -1, -7
-6, 0, 0
Step-by-step explanation:
x
x+6
7(x+6)
7(x+6)+ x(x+6) = 0
(x+6)(7+x) = 0
x = -6, -7
-6, 0, 0
-7, -1, -7