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Katyanochek1 [597]
3 years ago
9

J is the midpoint of hk. what is hj, jk, and hk

Mathematics
2 answers:
Lyrx [107]3 years ago
4 0
Hj and jk are the same length line segments ( because the midpoint divides a line into two equal parts)
So hj = jk.

hk is the line segment which has the mid point j. It is the double of hj or jk. It can be the sum of hj and jk. 
hj + jk = hk 
      or
2 * hj = hk
      or 
2 * jk = hk
kari74 [83]3 years ago
4 0

Answer:

The answer is 'b'  on Edg

Step-by-step explanation:

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Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
Free_Kalibri [48]

Answer:

1/3

Step-by-step explanation:

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

Each side of Polygon FFF was multiplied by a certain value, known as the scale factor , to result in an area that is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

[Show me an example of how scale factor affects area]

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction

 

 

\begin{aligned} A &= \left(l\times\dfrac1{10}\right)\times\left(w\times\dfrac1{10}\right) \\ \\ A&= l\times w\times\dfrac1{10}\times\dfrac1{10} \\ \\ A&= lw \times \left(\dfrac1{10}\right)^2\end{aligned}  

 

 

 

 

 

 

 

 

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction\left(\dfrac1{10}\right)^2  

 

left parenthesis, start fraction, 1, divided by, 10, end fraction, right parenthesis, start superscript, 2, end superscript

Hint #22 / 3

The area of a polygon created with a scale factor of \dfrac1x  

x

1

​  start fraction, 1, divided by, x, end fraction has \left(\dfrac1{x}\right)^2(  

x

1

​  )  

2

left parenthesis, start fraction, 1, divided by, x, end fraction, right parenthesis, start superscript, 2, end superscript the area of the original polygon:

\left(\text{scale factor}\right)^2=\text{fraction of the area the scale copy has}(scale factor)  

2

=fraction of the area the scale copy hasleft parenthesis, s, c, a, l, e, space, f, a, c, t, o, r, right parenthesis, start superscript, 2, end superscript, equals, f, r, a, c, t, i, o, n, space, o, f, space, t, h, e, space, a, r, e, a, space, t, h, e, space, s, c, a, l, e, space, c, o, p, y, space, h, a, s

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF. Let's substitute \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction into the equation to find the scale factor.

\left(\dfrac1{?}\right)^2=\dfrac19(  

?

1

​  )  

2

=  

9

1

​  left parenthesis, start fraction, 1, divided by, question mark, end fraction, right parenthesis, start superscript, 2, end superscript, equals, start fraction, 1, divided by, 9, end fraction

The scale factor is \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction.

Hint #33 / 3

Aimar used a scale factor of \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction to go from Polygon FFF to Polygon GGG.

4 0
3 years ago
Read 2 more answers
Find two integers whose difference is -6. ( There are many!)
olga nikolaevna [1]

Step-by-step explanation:

There are infinitely many such integers.

x - y = -6            <em>add y to both sides</em>

x = -6 + y → x = y - 6

1. Choose any y value.

2. Substitute for the equation.

3. Calculate the value of x.

Examples:

for y = 0 → x = 0 - 6 = -6

check: -6 - 0 = -6

for y = 10 → x = 10 - 6 = 4

check: 4 - 10 = -6

for y = -9 → x = -9 - 6 = -15

check: -15 - (-9) = -15 + 9 = -6

5 0
3 years ago
during the day Sam spent $4.85 on lunch he also bought 2 books for $7.95 each at the end of the day he had $8.20 left. how much
prisoha [69]

Answer:

$28.95

Step-by-step explanation:

$14.85 + 15.90= 20.75 + 8.20= 28.95

7 0
3 years ago
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15gal. mulch cover 5 flowerbeds how many to cover 7 flowerbeds=
shutvik [7]
It would take 21gal to cover 7 flowerbeds. Hope this helps! :D
4 0
3 years ago
HELP!!!!HELP!!!!HELP!!!!HELP!!!!
iren [92.7K]

Answer:

B

Step-by-step explanation:

From the figure, its clear that the compass drew arcs like below:

With A as centre, and more than half of the length of AB as radius, one arc is drawn.

With the same radius, with B as centre, another arc is drawn.

The points of intersections of the arcs are X and Y.

Clearly, this is the construction of a perpendicular bisector of the line segment AB.

Hence, if we draw a line segment through XY, it will be a perpendicular bisector of AB.

Step-by-step explanation:

8 0
3 years ago
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