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UNO [17]
3 years ago
7

A football team gains 18 yards in one play and then loses 12 yards in the next. What is the team's total yardage?

Mathematics
2 answers:
Sav [38]3 years ago
5 0
The teams total yardage is 6 yards
nikitadnepr [17]3 years ago
5 0

Answer: 6 yards.

Step-by-step explanation:

Given : The gain in play to the football team = 18 yards

By using integers , it can be written as +18.

The loss in the next play = 12 yards

By using integers , it can be written as -12

Then, the team's total yardage is given by :-

\text{Total yardage}=18\text{ yards}-12\text{ yards}\\\\\Rightarrow\ \text{Total yardage}=6 \text{ yards}

Hence, the team;s total yardage = 6 yards.

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4(x-3)-(2x+5)=-3x-27
Georgia [21]
4(x-3)-(2x+5)=-3x-27
4*x - 4*3 - 2x - 5 = -3x - 27
4x - 12 - 2x - 5 = -3x - 27
2x - 17 = -3x - 27
2x + 3x = -27 + 17
5x = -10 / : 5
x = -2

7 0
3 years ago
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50 POINTS PLEASE HELP! In order to rewrite log9 (6/5) as log9 (6) - log9 (5) , which of the following is used?
Anna11 [10]
B. Is the correct answer.
3 0
3 years ago
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sixteen dictionaries weigh 11.52 pounds all together. each dictionary has the same weight in pounds,how much does one dictionary
iogann1982 [59]

Answer:

1.92 Pounds per dictionary


Step-by-step explanation:

Since 6 dictionaries weigh 11.52 pounds, and each of the dictionaries weigh the same, this is a simple division problem.

11.52/6=1.92


3 0
3 years ago
Either enter an exact answer in terms of \piπpi or use 3.14, point, 14 for \piπpi and enter your answer as a decimal.
OverLord2011 [107]

Answer:

49π sq. units

Step-by-step explanation:

Find the diagram attached

We can find the area of the given circle

Given

diameter of the circle d = 14

Area of the circle = πd²/4

Substitute the given diameter

Area of the circle = π(14)²/4

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Hence the exact answer in terms of π is 49π sq. units

4 0
2 years ago
.Given the functions f(n) = 500 and g(n) = (nine tenths)n _ 1, combine them to create a geometric sequence, an, and solve for th
weeeeeb [17]
The original functions are: f(n) = 500 and g(n) = [9/10]^(n-1)

A geometric sequence combining them is: An = f(n)*g(n) = 500*[9/10]^(n-1):

Some terms are:
A1= 500
A2 = 500*[9/10]
A3 = 500*[9/10]^2
A4 = 500*[9/10]^3
....
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Answer: the third option, An = 500[9/10]^(n-1); A11 = 174.339

 
4 0
3 years ago
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