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kupik [55]
3 years ago
14

EXTRA POINTS

Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0
If the problem want rational coefficient, then u need additional zero -1-√5 so you will expand a polynomial
(x+2)(x-2)²(x-1-√5)(x-1+√5). otherwise not necessary ie
(x+2)(x-2)²(x-1-√5).
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How to work -1x-2y=-13 x-2y=11 equation by substitution
Norma-Jean [14]
Well if you're wanting to use substitution, you first have to end up with one term on either side of the equation. Use the second one as it's easiest. 

So: x-2y=11, so find -2y as there is a -2y in the first equation. 
then that becomes -2y=11-x. then sub that into equation 1, and you get:

-x+11-x=-13, which equals to -2x+11=-13, which is -2x=-24, so therefore

x=12. then chuck the x into any of the equations to find what y equals. 

hope this helps!
5 0
3 years ago
7-(-12)=7+(-12)=-5 describe and correct the error in finding the difference 7-(-12)
valina [46]

Answer:

7 - (-12) = 7 + 12 = 19

Step-by-step explanation:

- (-12) is a double negative which means that the minus signs cancel out causing it to to be a positive 12

5 is not the answer because 7 + 12 is 19

3 0
3 years ago
Read 2 more answers
Repeated decimals can be written as an infinite geometric series to help convert them to a fraction. Consider the repeating deci
Oksi-84 [34.3K]

Answer:

a1= 0.23

r=0.01

:)

Step-by-step explanation:

7 0
3 years ago
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When a fair coin is flipped, what is the chance of getting about 50% heads- specifically between 40% and 60% heads for n=10 flip
aleksklad [387]
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
3 0
2 years ago
El resultado de la adición 1/3 + 1/9 es =?
murzikaleks [220]

Answer:

4/9

Step-by-step explanation:

You're welcome i worked it out on a piece of paper

5 0
3 years ago
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