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4 years ago

15. Explain how to round 768 to the hundreds place. Topic 4

Mathematics

2 answers:

Viktor [21]4 years ago

5 0

The number 768 is higher than 750 so it would be 800 rounded to the hundredths place

o-na [289]4 years ago

4 0

Answer: You look at the ten place and if its over than 50, it is rounding up. If it below 50, it is rounding down.

Step-by-step explanation:

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a hockey team ordered 12 wooden pedestals to mount their brass trophies on. The design pedestal is shown below. The teal is char

yKpoI14uk [10]

56 cause u need 12 divide by 0.08 12 times

8 0

3 years ago

Read 2 more answers

Line A. C. D. B. Defined Postulates Theorems Undefined Terms

oksian1 [2.3K]

Answer: Undefined

Step-by-step explanation:

In geometry there are three undefined terms that we use to define other terms:

Point → In geometry a point has a location but no dimension.
Plane → A plane extends is a 2-dimensional surface that extends infinitely on both sides.
Line → A line is a one-dimensional undefined figure that extends infinitely in both the directions. It has length but has no width.

Hence, the correct option is "Undefined".

8 0

3 years ago

A scale drawing of a building is one foot to 1/4 inch. What is the actual length of the building if the scale drawing shows that

Rom4ik [11]

$1\quad foot\quad :\quad \frac { 1 }{ 4 } \quad inch\\ \\ 4\quad \cdot \quad 1\quad foot\quad :\quad \frac { 1 }{ 4 } \quad inch\quad \cdot \quad 4\\ \\ 4\quad feet\quad :\quad 1\quad inch$

This means that:

$4\quad feet\quad :\quad 1\quad inch\\ \\ \frac { 27 }{ 2 } \cdot \quad 4\quad feet\quad :\quad \frac { 27 }{ 2 } \cdot \quad 1\quad inch\\ \\ \frac { 108 }{ 2 } \quad feet\quad :\quad \frac { 27 }{ 2 } \quad inches\\ \\ 54\quad feet\quad :\quad \frac { 27 }{ 2 } \quad inches\\ \\$

13 + 1/2 inches is the same as 54 feet

4 0

3 years ago

Read 2 more answers

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

3 years ago

What answer would this be (-3)(-5)(0)

DIA [1.3K]

-3 × -5 = -15
-15 × 0 = 0

6 0

4 years ago