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tigry1 [53]
3 years ago
9

Can someone show me how to even start with 1 and 2? ​

Mathematics
1 answer:
diamong [38]3 years ago
6 0

All you need to know is that

\displaystyle \lim_{x\to\infty}a^x=\begin{cases} \infty \text{ if } a>1\\1 \text{ if } a=1\\0 \text{ if } 0\leq a

So, the first function grows exponentially and the second decays exponentially. The rate of growth/decay are the bases of the exponentials, which means 1.08 and 0.205

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Answer:

I think your right

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Step-by-step explanation:

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3 years ago
Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.
Yakvenalex [24]

Answer: x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

Step-by-step explanation:

2x^2-9x+5

a=2

b=-9

c=5

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)}  }{2(2)}

x=\frac{9\frac{+}{}\sqrt{81-40}  }{4}

x=\frac{9\frac{+}{}\sqrt{41}  }{4}

x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

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