Answer:
Cost of a single Mucho beef burrito:
Cost of a double Mucho beef burrito:
Step-by-step explanation:
<h3> The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.
Set a system of equations:
To solve this system you can apply the Substitution Method:
1. Substitute the second equation into the first equation and solve for "y":
2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":
Answer:
the second option
Step-by-step explanation:
in ax²+bx+c = 0:
subtract both sides by 6 to get to this form, as the right side will be left with 0
6x² + 8x - 6 = 0
here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6
plugging our numbers into the formula, we get
Last Question
Because this may not be the question you want, I'll omit the first step which should be done with latex. The key to all of these except C is to invert the second fraction (turn the second fraction upside down) and multiply.
A
=(6*-2) / (5*3) = - 12/15 = -4/5
B
= (7*5) / (4*3) = 35 / 12 = 2 11/12
C
Impossible to do 4/0 cannot be done.
D
= (-2*-4)/(3*5) =
8/15