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m_a_m_a [10]
3 years ago
10

Parents enter the Echo stage when

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0
When the last child has finished his or her schooling and is no longer dependent on the parents, the Echo stage begins. This is the pre-retirement or "empty nest" stage. For those individuals without children, the Echo stage begins about 10 years before retirement.
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7.325 divided by 1.465​
ki77a [65]
The correct answer for 7.325 divided by 1.465 is 5
7 0
4 years ago
Read 2 more answers
HELP !! ASAP !!
Sedaia [141]

Answer:

The roots are;

x = (2 + i)/5 or (2-i)/5

where the term i is the complex number representing the square root of -1

Step-by-step explanation:

Here, we want to use the completing the square method to solve the quadratic equation;

f(x) = -5x^2 + 4x -1

Set the function to zero

0 = -5x^2 + 4x - 1

So;

-5x^2 + 4x = 1

divide through by the coefficient of x which is -5

x^2 - 4/5x = -1/5

We now take half of the coefficient of x and square it

= -2/5^2 = 4/25

add it to both sides

x^2 - 4x/5 + 4/25= -1/5 + 4/25

(x- 2/5)^2 = -1/5 + 4/25

(x - 2/5)^2 = -1/25

Take the square root of both sides

x - 2/5 = √( -1/25

x - 2/5 = +i/5 or -i/5

x = 2/5 + i/5 or 2/5 - i/5

7 0
3 years ago
What is the quotient when (x+3) is divided into the polynomial 2x2+3x-9
maks197457 [2]
Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3



4 0
3 years ago
Read 2 more answers
Sam rotated parallelogram ABCD 270 counter clockwise around the origin if angle a is 120 and angle B 60 what is the degree measu
jarptica [38.1K]

Given that ABCD is a parallelogram.

where angle B is 60 degree.

Notice that only parallelogram is rotated. Rotation doesn't changes the name of angles. So angle B will remain at it's position.

Hence value of angle B will also not change.

So final answer for the value of angle B is 60 degree.

4 0
3 years ago
Can someone help me solve this differentiation/tangent problem?
nirvana33 [79]
A)

\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot  f'(x)}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\
-------------------------------\\\\
g(5)=(5)^2f(5)\implies g(5)=125
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}
\begin{cases}
x=5\\
y=125\\
\stackrel{m}{g'(5)}=550
\end{cases}\implies y-125=550(x-5)
\\\\\\
y-125=550x-2750\implies y=550x+400



b)

\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}
\\\\\\
h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\
-------------------------------\\\\

\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad 
\begin{cases}
x=5\\
y=-5\\
\stackrel{m}{-10}
\end{cases}\implies y-(-5)=-10(x-5)
\\\\\\
y+5=-10x+50\implies y=-10x+45
3 0
4 years ago
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