Question

Which of these functions has a domain of all real numbers except x=4.1?

Answer 1

Answer:

$(A)y=\frac{2.5}{x-4.1} + 2.8$

Step-by-step explanation:

In the expressions, the value at which the domain of the function will be the set of all real numbers except x=4.1 is the value at which 4.1 makes the denominator equal to zero, i.e makes the fraction undefined.

Given the options

$(A)y=\frac{2.5}{x-4.1} + 2.8$

Setting the denominator to zero, x-4.1=0, x=4.1. The fraction is undefined at x=4.1

$(B)y=\frac{2.8}{x+4.1} -2.5$

Setting the denominator to zero, x+4.1=0, x=-4.1. The fraction is undefined at x=-4.1

$(C)y=\frac{4.1}{x-2.8} +2.5$

Setting the denominator to zero, x-2.8=0, x=2.8. The fraction is undefined at x=2.8

$(D)y=\frac{4.1}{x-2.5} +2.8$

Setting the denominator to zero, x-2.5=0, x=2.5. The fraction is undefined at x=2.5

Therefore, function that has a domain of all real numbers except x=4.1 is:

$(A)y=\frac{2.5}{x-4.1} + 2.8$